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Results tagged with inorganic-chemistry
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user 56637
Inorganic compounds generally do not have C-H bonds, while organic compounds do have such bonds. The distinction between inorganic and organic chemistry, however, is far from absolute.
8
votes
Why are copper salts less soluble than zinc salts?
It is because the difference in electronegativity.
The higher the difference in electronegativity between the cation and the anion, the stronger the ionic bond.
Since we are comparing species with t …
- 12.7k
10
votes
Accepted
Dissolution of Lithium in Methanol
I have not done it with lithium but many times with sodium. Lithium is the less reactive, so it should not give more problems. We use sodium to dry methanol, so it is a common operation in the lab. Th …
- 4,402
1
vote
Accepted
Electrochemical manufacturing of small metal components
Nice idea, but difficult to do.
The copper cations must continuously enter the "mold" electrode to grow there, but they must not be able to grow outside.
If there are holes in the "mold" the crysta …
- 4,402
0
votes
Separation of solvent from residue of material.
Distillation is the way to go. Especially if you have to do it on industrial scale (if we have understood well, you have 2000 L to process).
Normally it yields recovered solvent with low level of imp …
- 4,402
1
vote
Do acids react with neutral salts?
Neutralization is a reaction between acid and base which results in the formation of a salt and water.
When you have any ionic compound and dissolve it into water, dissociation occurs.
This means that …
- 4,402
1
vote
Does deuterium exhibit hydrogen bonding?
In short:
Chemistry is about the last shell of electrons in the atoms.
Nuclear differences are in the field of Physics.
Deuterium is only a nuclear isotope of hydrogen, so no fundamental difference …
- 4,402
5
votes
Is it a redox reaction if the oxidation state of the element has changed only in one of the ...
One sulphuric acid is used to form sodium sulphate and the other one is used for oxidizing.
So you have a reduction:
$\ce{4H+ + SO4^2- +2e- -> SO2 + 2H2O}$
and an oxidation:
$\ce{2Br- -> Br2 +2e^- …
- 26.8k