15
$\begingroup$

The following amino acid is called lysine. I was asked to calculate its isoelectric point, with the given $\mathrm pK_\mathrm a$ values.

lysine-structure-with-pka-values

I've searched a lot, and the most helpful post that I found was How do I calculate the isoelectric point of amino acids with more than two pKa's? According to orthocresol's answer:

Since the $\mathrm{pI}$ is the $\mathrm{pH}$ at which the amino acid has no overall net charge, you need to average the $\mathrm pK_\mathrm a$ values relevant to the protonation/deprotonation of the form with no net charge.

Let's call the ends $e_1, e_2$ and $e_3$ (from left to right).

Approach $\#1$

  • deprotonate $e_3$ (i.e., carboxyl group)
  • deprotonate $e_1$ or $e_2$ [neutral point]

So, $\mathrm pK_\mathrm a$'s of $e_1$ and $e_2$ are relevant.

$$\Rightarrow \mathrm{pI} = \frac{10.53 + 8.95}{2} = 9.74$$

But, is there some limit to number of protonations/deprotonations or some procedures to follow?

For instance,

Approach $\#2$

  • deprotonate $e_1$
  • deprotonate $e_3$ [neutral point]
  • deprotonate $e_2$ and protonate $e_1$ [neutral point]

This time, $\mathrm pK_\mathrm a$'s of $e_3$ and $e_1$ are relevant. But, the calculated $\mathrm{pI}$ isn't correct.

So, how can I validate the approaches?


Problem source: FIITJEE study material

$\mathrm pK_\mathrm a$ and $\mathrm{pI}$ values table for amino acids: https://www.anaspec.com/html/pK_n_pl_Values_of_AminoAcids.html

$\endgroup$
2
  • 1
    $\begingroup$ The first approach I'd say is the correct one. It's obvious that the isoelectric point will be between e1 and e2 because lysine is a dibasic aminoacid, therefore the two amino groups will have a bigger influence on the pI than the acidic group, thus rendering the pI basic. In these cases, as far as I know, you have to find the average of 2 pKa-values that are going to have the biggest influence on the pI. In this case, since there are 3 pKa-values of which 2 are basic, the pI will be the arithmetic mean of those values. $\endgroup$ Commented Jul 18, 2020 at 14:21
  • 1
    $\begingroup$ Related: Various pI calculators for proteins give different results: ExPASy (8.75), isoelectric.org (9.04), and Prot pi (8.475). $\endgroup$ Commented Jul 19, 2020 at 12:53

1 Answer 1

13
$\begingroup$

Isoelectric point of an amino acid is the $\mathrm{pH}$ at which the molecule carries no net charge[1]. It can be calculated by the average of the relevant $\mathrm pK_\mathrm a$ values as you have mentioned.

Your confusion seems to stem from choosing the relevant $\mathrm pK_\mathrm a$ values. For this we should refer to the titration curve of the amino acid.

For a neutral amino acid[2]:

titration curve 1

From the curve we can infer that the $\mathrm{pI}$ is simply the average of the two $\mathrm pK_\mathrm a$ values of the carboxylic acid and the amino group.

For a basic amino acid[2]:

titration curve 2

From the curve we can infer that the $\mathrm{pI}$ is simply the average of the two $\mathrm pK_\mathrm a$ values of the two amino groups. The $\mathrm pK_\mathrm a$ of the carboxylic acid group is not relevant.

For an acidic amino acid[3]:

enter image description here

From the curve we can infer that the $\mathrm{pI}$ is simply the average of the two $\mathrm pK_\mathrm a$ values of the two carboxylic acid groups. The $\mathrm pK_\mathrm a$ of the amino group is not relevant.

Here are examples for all three cases:

enter image description here

References:

  1. Wikipedia

  2. Titration curves for neutral and basic amino acids

  3. Titration curve for acidic amino acids

$\endgroup$
2

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.