The following amino acid is called lysine. I was asked to calculate its isoelectric point, with the given $\mathrm pK_\mathrm a$ values.
I've searched a lot, and the most helpful post that I found was How do I calculate the isoelectric point of amino acids with more than two pKa's? According to orthocresol's answer:
Since the $\mathrm{pI}$ is the $\mathrm{pH}$ at which the amino acid has no overall net charge, you need to average the $\mathrm pK_\mathrm a$ values relevant to the protonation/deprotonation of the form with no net charge.
Let's call the ends $e_1, e_2$ and $e_3$ (from left to right).
Approach $\#1$
- deprotonate $e_3$ (i.e., carboxyl group)
- deprotonate $e_1$ or $e_2$ [neutral point]
So, $\mathrm pK_\mathrm a$'s of $e_1$ and $e_2$ are relevant.
$$\Rightarrow \mathrm{pI} = \frac{10.53 + 8.95}{2} = 9.74$$
But, is there some limit to number of protonations/deprotonations or some procedures to follow?
For instance,
Approach $\#2$
- deprotonate $e_1$
- deprotonate $e_3$ [neutral point]
- deprotonate $e_2$ and protonate $e_1$ [neutral point]
This time, $\mathrm pK_\mathrm a$'s of $e_3$ and $e_1$ are relevant. But, the calculated $\mathrm{pI}$ isn't correct.
So, how can I validate the approaches?
Problem source: FIITJEE study material
$\mathrm pK_\mathrm a$ and $\mathrm{pI}$ values table for amino acids: https://www.anaspec.com/html/pK_n_pl_Values_of_AminoAcids.html