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Can anyone propose/draw a mechanism for Method A, below, from this paper? Almost all other literature use method B and reagents such as SOCl2. enter image description here

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    $\begingroup$ Welcome to ChemSE; Unless you offer a solution to this question it will be voted down. We do not do homework but we will help you with some effort on your part. Get back to us. $\endgroup$
    – user55119
    Commented Aug 7, 2019 at 20:46
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    $\begingroup$ What is the role of AlCl3? What is its reactivity? How about the lactone? $\endgroup$
    – Raphaël
    Commented Aug 7, 2019 at 21:10
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    $\begingroup$ My best shot is: the ring breaks in order to stabilize the activated oxygen. I am unsure whether it is at the 2 or 4 carbon... I am then unsure as to whether there is a hydride shift, whether an acylium or carboxylic acid group forms, how to remove the hydroxyl group, and how the benzene attacks... $\endgroup$
    – JBG
    Commented Aug 7, 2019 at 22:05
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    $\begingroup$ Additionally I have found several papers that show that this reaction does not proceed eg reader.elsevier.com/reader/sd/pii/… $\endgroup$
    – JBG
    Commented Aug 7, 2019 at 22:06
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    $\begingroup$ @JBG you can include all the information of yours in the comments into your question to make it more contextual rather than a mere homework question. $\endgroup$ Commented Aug 8, 2019 at 4:47

1 Answer 1

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The reaction of benzene and γ-butyrolactone with AlCl3 was reported by Truce and Olson1 in 1952. The authors found that the ratio of γ-phenylbutyric acid to α-tetralone was dependent on the AlCl3/lactone ratio. The larger the latter ratio; the more α-tetralone. (See Table 1 from the paper). The ratio employed in the Organic Syntheses preparation is 3.7. Table 2 from Truce's paper provides an explanation for the role of excess AlCl3 but it doesn't explain the alkylation of benzene.

The lactone-AlCl3 complex 1 can act as an electrophile aromatic alkylation (1-->2-->3). Subsequent intramolecular acylation of 4 leads to α-tetralone 6. Bear in mind that γ-butyrolactone reacts with HBr to form γ-bromobutyric acid.

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1) W. E. Truce and C. E. Olson, J. Am. Chem. Soc., 1952, 74, 4721.

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