How does benzene react with $\ce{NaNO2/HCl}$? Will $\ce{PhNO}$ be obtained? I read that pyridine can be produced under special conditions, but what will happen in some less exotic conditions?
$\begingroup$
$\endgroup$
1
-
$\begingroup$ Afaik, $\ce{NO^+}$-cation is too weak as electrophile to react with benzene, nitrosobenzene is obtained indirectly. $\endgroup$– permeakraCommented Sep 1, 2014 at 13:40
Add a comment
|
1 Answer
$\begingroup$
$\endgroup$
0
As you noted, the link you provided was to a reaction run under rather exotic conditions (low-temperature plasma). Under more everyday laboratory conditions, for example, in solution, activated aromatic rings can react with $\ce{NO^+}$ as shown below.
However if there is a ring-activating amino substituent present, then the $\ce{NO^+}$ will react with the nitrogen to produce the synthetically important diazonium ion.
