I know that Friedel Crafts alkylation reaction are not possible for aniline and phenol since they form complexes with Lewis Acids. But our teacher told us that Friedel Crafts reactions aren't possible for any benzene derivative which is less activated than benzene. Why does that happen?

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    $\begingroup$ Strong electron-withdrawing groups deactivate the ring by reducing the electron denisity available to the attacking cationic species and to stabilise the intermediate cation. $\endgroup$ – Waylander Mar 30 at 13:05
  • $\begingroup$ Also, aniline and phenol would be more activated than benzene since the electron density on the rind would be higher otherwise. $\endgroup$ – Eashaan Godbole Mar 30 at 13:48
  • $\begingroup$ You should ask your teacher to explain how the FC alkylation actually works. Recognising dis/activating substituents is elementary, and not by learning them by heart! Don´t you have a proper textbook? $\endgroup$ – Karl Mar 30 at 19:41

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