Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with stability
Search options not deleted
user 85319
Applied to a chemical species, the term expresses a thermodynamic property in reference to a standard, stating that one state is lower in energy than another. The tag should be applied to questions seeking answers with respect to the stability (or instability) of a certain chemical species, molecular entity and/or electronic structure. It must not be applied to questions about the reactivity of particular chemical species.
-2
votes
1
answer
75
views
Energy lost due to stability [closed]
So from where does the energy come which is lost by an atom to achieve stability.
Do electrons lose energy? …
1
vote
Which resonance structure would be favorably contributed to the actual structure?
In (b) part negative charge is on less electronegative atom carbon so it will hold negative charge loosely in comparison to oxygen. So resonance can happen more betterly in second one.
In (g) part ac …
-1
votes
Para effects on substituents in aromatic compounds
At meta position the M effect is not considered. The reason behind is that during resonance of a six membered cyclic compound charges never reaches at meta position that why it is so try to proof it b …