5
$\begingroup$

Question Regarding Carbocation

In the above reaction, clearly the OH will be protonated followed H2O leaving, seeing that it's a good leaving group.

Now there can be two possibilities either a alkene is formed as is, or the carbocation rearranges and ends up opening the ring, thus increasing the final stability of molecule, followed by alkene formation. (5 carbon ring is more stable)

But as per some texts, the Carbocation only rearranges until the neighbouring carbon and then alkene is formed without ring opening. Is that correct, if yes, why?

Improve this question
$\endgroup$

1 Answer 1

Reset to default
3
$\begingroup$

Consider that in the situation you present, it would be much easier to lose the proton to form the alkene immediately, than to migrate the positive charge until a position where ring-opening is viable.

Not to say it is impossible, but the required 'steps' to get to that point are very improbable to the point that it doesn't happen.

Improve this answer
$\endgroup$
1
  • $\begingroup$ I think that this certainly is the correct approach. Also, my professor mentioned that carbocation rearranges to the adjacent carbon only if the new intermediate carbocation is more stable. Clearly, here, after one rearrangement, no more stability can be achieved by rearranging to neighbouring carbon, and hence it forms an alkene. $\endgroup$
    – AnonMouse
    Commented Jul 11, 2016 at 20:50

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.