I am currently working on a total synthesis strategy, but I was told that a key step in my total synthesis probably wouldn't work, so now I am trying to figure out a way around it. The compound that I need to make is (S)-2-hydroxy-4-oxohex-5-enal 4(see structure, aldehyde is protected as a thioacetal). I first considered an asymmetric aldol reaction between 2 and 3, but since the proton on the tertiary carbon of 2 is probably the most acidic and the other ketone is likely to undergo conjugate addition, the chances of this reaction happening in the right direction are small. I have been considering starting from (R)-glycidol and then do a ring-opening with an enolate, but literature seems to indicate that enolates do not readily attack epoxides. Does anyone have a suggestion for a direction?
2 Answers
I agree with @Waylander that the synthesis of (S)-2-hydroxy-4-oxohex-5-enal (7) by asymmetric means may be problematic. Why not start with what Mother Nature gives you---glucose. Diacetone glucose (1; DAG) is readily prepared and commercially available. The conversion of DAG to unsaturated acetonide 2 has been accomplished. The authors[1] removed the $\ce{C3-OH}$ by a modified Barton radical deoxygenation. Subsequent selective hydrolysis of the $\ce{C5-C6}$ acetonide (aq. HOAc) and bis-deoxygenation via $\ce{Me2NCH(OMe)2}$. Treatment of unsaturated acetonide 2 with $\ce{MeOH/H+}$ leads to a presumed mixture of unsaturated acetals 4. Inversion of the $\ce{C2-OH}$ stereochemistry via mesylation and potassium superoxide displacement[2] affords 4. Other oxygen nucleophiles may be considered. Ethylene glycol acetal 5 should be favored entropically over 4 given the bis-functionality of ethylene glycol. Any equilibrium may be favored by distillation or absorption (molecular sieves) of methanol. Finally, selective allylic oxidation of diol 5 with $\ce{MnO2}$ affords the enone 6. Hydrolysis of the acetal moiety of 6 leads to the target compound 7. This hydrolysis may well be problematic with β-elimination looming. Alternatively, the route 4 → 8 → 7 may prove superior give the mild Fetizon conditions for cleavage of the dithiane group of 8.
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$\begingroup$ That is very helpful, thank you so much! $\endgroup$ Commented Jun 2 at 8:01
After consultation with former colleagues, we think your best option is to react 2 with an chiral enamine of 3 under mild Lewis acid catalysis (something like Sn(OEt)4)