I'm given this equation in word form:

$$\rm sodium \:(s) + water\: (aq) \ce{->} unknown ~products\:(s/g/aq)$$ and I have to convert this to a chemical equation. I understand how to covert this normally, that equation can hence be represented by:

$$\ce{Na + H2O -> unknown~products\:(s/g/aq)}$$ This is indeed a single displacement reaction so it should become (according to what I know so far) $\ce{Na2O + H2}$ but after doing some research, I got that it should be:

$$\ce{Na + H2O -> NaOH + \frac{1}{2}H2}$$ or $$\ce{2Na + 2H2O -> 2NaOH + H2}$$

I'm lost now, where did $\ce{NaOH}$ come from? Especially the H since there is no reason for Hydrogen to be present.

Please explain why and how to balance this reaction or convert this and what factors to look at when dealing with these types of equations.

I'm given this equation in word form:

$$\ce{sodium (s) + water (aq) -> unknown~products (s/g/aq)}$$

and I have to convert this to a chemical equation. I understand how to covert this normally, that equation can hence be represented by:

$$\ce{Na + H2O -> unknown~products\:(s/g/aq)}$$ 

This is indeed a single displacement reaction so it should become (according to what I know so far) $\ce{Na2O + H2}$ but after doing some research, I got that it should be:

$$\ce{Na + H2O -> NaOH + \frac{1}{2}H2}$$ or $$\ce{2Na + 2H2O -> 2NaOH + H2}$$

I'm lost now, where did $\ce{NaOH}$ come from? Especially the H since there is no reason for hydrogen to be present.

Please explain why and how to balance this reaction or convert this and what factors to look at when dealing with these types of equations.

So I'm given this equation in word form:

$$\rm Sodium \:(s) + water\: (aq) \ce{->} Unknown~Products\:(s/g/aq)$$ and I have to convert this to a chemical equation. I understand how to covert this normally, that equation can hence be represented by:

$$\ce{Na + H2O -> Unknown~Products\:(s/g/aq)}$$ This is indeed a single displacement reaction so it should become (according to what I know so far) $\ce{Na2O + H2}$ but after doing some research, I got that it should be:

$$\ce{Na + H2O -> NaOH + \frac{1}{2}H2}$$ or $$\ce{2Na + 2H2O -> 2NaOH + H2}$$

I'm so lost now, where did $\ce{NaOH}$ come from? Especially the H since there is no reason for Hydrogen to be present.

Please explain why and how to balance this or convert this and what factors to look at when dealing with these types of equations.

Any help is appreciated... Thanks!

I'm given this equation in word form:

$$\rm sodium \:(s) + water\: (aq) \ce{->} unknown ~products\:(s/g/aq)$$ and I have to convert this to a chemical equation. I understand how to covert this normally, that equation can hence be represented by:

$$\ce{Na + H2O -> unknown~products\:(s/g/aq)}$$ This is indeed a single displacement reaction so it should become (according to what I know so far) $\ce{Na2O + H2}$ but after doing some research, I got that it should be:

$$\ce{Na + H2O -> NaOH + \frac{1}{2}H2}$$ or $$\ce{2Na + 2H2O -> 2NaOH + H2}$$

I'm lost now, where did $\ce{NaOH}$ come from? Especially the H since there is no reason for Hydrogen to be present.

Please explain why and how to balance this reaction or convert this and what factors to look at when dealing with these types of equations.

So I'm given this equation in word form:

Sodium (s) + water (aq) → Unknown Products (s/g/aq) and I have to convert this to a chemical equation... I understand how to covert this normally, that equation can hence be represented by:

Na + H2O → Unknown Products (s/g/aq). This is indeed a single displacement reaction so it should become (according to what I know so far):

Na2O + H2 but after doing some research, I got that it should be:

Na + H2O --> NaOH + (1/2)H2 or 2Na + 2H2O --> 2NaOH + H2.

Im so lost now, where did NaOH come from? Especially the H since there is no reason for Hydrogen to be present.

Please explain why and how to balance this or convert this and what factors to look at when dealing with these types of equations...

Any help is appreciated... Thanks!

So I'm given this equation in word form:

$$\rm Sodium \:(s) + water\: (aq) \ce{->} Unknown~Products\:(s/g/aq)$$ and I have to convert this to a chemical equation. I understand how to covert this normally, that equation can hence be represented by:

$$\ce{Na + H2O -> Unknown~Products\:(s/g/aq)}$$ This is indeed a single displacement reaction so it should become (according to what I know so far) $\ce{Na2O + H2}$ but after doing some research, I got that it should be:

$$\ce{Na + H2O -> NaOH + \frac{1}{2}H2}$$ or $$\ce{2Na + 2H2O -> 2NaOH + H2}$$

I'm so lost now, where did $\ce{NaOH}$ come from? Especially the H since there is no reason for Hydrogen to be present.

Please explain why and how to balance this or convert this and what factors to look at when dealing with these types of equations.

Any help is appreciated... Thanks!