Arrange the three types of hydrogens in 1‐ethynyl‐3‐methylbenzene in the order from the most acidic to the least.
From my understanding, the hydrogen on methyl would be the most acidic as the negative charge after removing the H would be in resonance.
The next one would be the the ethyne hydrogen because the negative charge after removing it would stay on a sp-carbon. The least acidic H would be the one from the benzene ring as the negative charge would fall on a sp2-carbon.
But the answer says the correct order is: ethyne's H > methyl's H > benzene ring's H. Where am I going wrong?