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In a saline solution that is 5.750% (m/v) potassium iodide $(\ce{KI}),$ there are:

 

a) 5.750 mL $\ce{KI}$ per 100.0 mL $\ce{H2O}$
b) 575.0 mg $\ce{KI}$ per 10.00 mL of $\ce{KI}$ solution
c) 5.750 g $\ce{KI}$ per 100.0 g $\ce{H2O}$
d) 5.750 g $\ce{KI}$ per 100.0 g of $\ce{KI}$ solution
e) 5.750 g $\ce{KI}$ per 100.0 mL of $\ce{H2O}$

I figured it should be e because for the equation of $(\text{m/v})\%$ is

$$(\text{m/v})\% = \frac{\text{mass solute (g)}}{\text{volume solution (ml)}}$$ and it's $\pu{g/100 mL},$ but it's not the correct answer.

In a saline solution that is 5.750% (m/v) potassium iodide $(\ce{KI}),$ there are:

 

a) 5.750 mL $\ce{KI}$ per 100.0 mL $\ce{H2O}$
b) 575.0 mg $\ce{KI}$ per 10.00 mL of $\ce{KI}$ solution
c) 5.750 g $\ce{KI}$ per 100.0 g $\ce{H2O}$
d) 5.750 g $\ce{KI}$ per 100.0 g of $\ce{KI}$ solution
e) 5.750 g $\ce{KI}$ per 100.0 mL of $\ce{H2O}$

I figured it should be e because for the equation of $(\text{m/v})\%$ is

$$(\text{m/v})\% = \frac{\text{mass solute (g)}}{\text{volume solution (ml)}}$$ and it's $\pu{g/100 mL},$ but it's not the correct answer.

In a saline solution that is 5.750% (m/v) potassium iodide $(\ce{KI}),$ there are:

a) 5.750 mL $\ce{KI}$ per 100.0 mL $\ce{H2O}$
b) 575.0 mg $\ce{KI}$ per 10.00 mL of $\ce{KI}$ solution
c) 5.750 g $\ce{KI}$ per 100.0 g $\ce{H2O}$
d) 5.750 g $\ce{KI}$ per 100.0 g of $\ce{KI}$ solution
e) 5.750 g $\ce{KI}$ per 100.0 mL of $\ce{H2O}$

I figured it should be e because for the equation of $(\text{m/v})\%$ is

$$(\text{m/v})\% = \frac{\text{mass solute (g)}}{\text{volume solution (ml)}}$$ and it's $\pu{g/100 mL},$ but it's not the correct answer.

Post Closed as "Not suitable for this site" by Todd Minehardt, Poutnik, DrMoishe Pippik, Mithoron, Mathew Mahindaratne
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In a saline solution that is 5.750% (m/v) potassium iodide $(\ce{KI}),$ there are:

a) 5.750 mL $\ce{KI}$ per 100.0 mL $\ce{H2O}$
b) 575.0 mg $\ce{KI}$ per 10.00 mL of $\ce{KI}$ solution
c) 5.750 g $\ce{KI}$ per 100.0 g $\ce{H2O}$
d) 5.750 g $\ce{KI}$ per 100.0 g of $\ce{KI}$ solution
e) 5.750 g $\ce{KI}$ per 100.0 mL of $\ce{H2O}$

I figured it should be e because for the equation of $\text{m/v})\%$$(\text{m/v})\%$ is

$$(\text{m/v})\% = \frac{\text{mass solute (g)}}{\text{volume solution (ml)}}$$ and it's $\pu{g/100 mL},$ but it's not the correct answer.

In a saline solution that is 5.750% (m/v) potassium iodide $(\ce{KI}),$ there are:

a) 5.750 mL $\ce{KI}$ per 100.0 mL $\ce{H2O}$
b) 575.0 mg $\ce{KI}$ per 10.00 mL of $\ce{KI}$ solution
c) 5.750 g $\ce{KI}$ per 100.0 g $\ce{H2O}$
d) 5.750 g $\ce{KI}$ per 100.0 g of $\ce{KI}$ solution
e) 5.750 g $\ce{KI}$ per 100.0 mL of $\ce{H2O}$

I figured it should be e because for the equation of $\text{m/v})\%$ is

$$(\text{m/v})\% = \frac{\text{mass solute (g)}}{\text{volume solution (ml)}}$$ and it's $\pu{g/100 mL},$ but it's not the correct answer.

In a saline solution that is 5.750% (m/v) potassium iodide $(\ce{KI}),$ there are:

a) 5.750 mL $\ce{KI}$ per 100.0 mL $\ce{H2O}$
b) 575.0 mg $\ce{KI}$ per 10.00 mL of $\ce{KI}$ solution
c) 5.750 g $\ce{KI}$ per 100.0 g $\ce{H2O}$
d) 5.750 g $\ce{KI}$ per 100.0 g of $\ce{KI}$ solution
e) 5.750 g $\ce{KI}$ per 100.0 mL of $\ce{H2O}$

I figured it should be e because for the equation of $(\text{m/v})\%$ is

$$(\text{m/v})\% = \frac{\text{mass solute (g)}}{\text{volume solution (ml)}}$$ and it's $\pu{g/100 mL},$ but it's not the correct answer.

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