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I have to draw curved arrows to convert the above molecule to its resonance structure but I'm not entirely sure how. I believe the sulfur atom has one lone pair and the oxygen atom has 2 lone pairs. But how would I be able to predict the location of the curved arrows?

I took a look at their formal charge and both seem to be 0.

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    $\begingroup$ Well, major resonance structures rarely involve tetrahedral carbons, so we can probably rule out any electron movement in the S-C single bonds. What do you think about the electron distribution in the S=O double bond? $\endgroup$
    – orthocresol
    Commented Sep 21, 2015 at 3:34
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    $\begingroup$ As another hint: Add all the electron pairs into the structure, it might give you an idea. (Also, the resonance structure you have drawn is no longer considered major ;)) $\endgroup$
    – Jan
    Commented Sep 21, 2015 at 8:46
  • $\begingroup$ oxygen is more electronegative so would a pi bond go to the oxygen atom and make that O-? $\endgroup$
    – nachime
    Commented Sep 21, 2015 at 13:41
  • $\begingroup$ Yes, but those would be only formal charges reflecting it's single dative bond $\endgroup$
    – Mithoron
    Commented Sep 21, 2015 at 23:14

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