Skip to main content
Tweeted twitter.com/StackChemistry/status/657252151245295616

Which is the stronger acid in the given pairs?

  1. $\ce{HClO3}$ and $\ce{HBrO3}$

  2. $\ce{HClO2}$ and $\ce{HClO}$

  3. $\ce{H2Se}$ and $\ce{H2S}$

  4. given that the #number of oxygensoxygen atoms is the same, the most electronegative atom should result in a stronger acid, thus $\ce{HCLO3}$$\ce{HClO3}$ is stronger.

  5. $\ce{HCLO2}$$\ce{HClO2}$ is stronger since it has more oxygen atoms.

  6. Here's where my logic fails, since the structure is the same (both have $\ce{2H+}$) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, sulfur is more electronegative thus stronger acid which was my original answer. But, the correct answer is $\ce{H2Se}$ is the stronger acid which implies in this case atomic size ($\ce{Se}$ is larger than $\ce{S}$) outweighs electronegativity. I do not understand why in this case $\ce{H2Se}$ is stronger than $\ce{H2S}$ given sulfur is more electronegative, and most importantly why the same logic used in 1. can't be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated.

Which is the stronger acid in the given pairs?

  1. $\ce{HClO3}$ and $\ce{HBrO3}$

  2. $\ce{HClO2}$ and $\ce{HClO}$

  3. $\ce{H2Se}$ and $\ce{H2S}$

  4. given that the # of oxygens is the same, the most electronegative atom should result in a stronger acid, thus $\ce{HCLO3}$ is stronger.

  5. $\ce{HCLO2}$ is stronger since it has more oxygen atoms.

  6. Here's where my logic fails, since the structure is the same (both have $\ce{2H+}$) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, sulfur is more electronegative thus stronger acid which was my original answer. But, the correct answer is $\ce{H2Se}$ is the stronger acid which implies in this case atomic size ($\ce{Se}$ is larger than $\ce{S}$) outweighs electronegativity. I do not understand why in this case $\ce{H2Se}$ is stronger than $\ce{H2S}$ given sulfur is more electronegative, and most importantly why the same logic used in 1. can't be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated.

Which is the stronger acid in the given pairs?

  1. $\ce{HClO3}$ and $\ce{HBrO3}$

  2. $\ce{HClO2}$ and $\ce{HClO}$

  3. $\ce{H2Se}$ and $\ce{H2S}$

  4. given that the number of oxygen atoms is the same, the most electronegative atom should result in a stronger acid, thus $\ce{HClO3}$ is stronger.

  5. $\ce{HClO2}$ is stronger since it has more oxygen atoms.

  6. Here's where my logic fails, since the structure is the same (both have $\ce{2H+}$) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, sulfur is more electronegative thus stronger acid which was my original answer. But, the correct answer is $\ce{H2Se}$ is the stronger acid which implies in this case atomic size ($\ce{Se}$ is larger than $\ce{S}$) outweighs electronegativity. I do not understand why in this case $\ce{H2Se}$ is stronger than $\ce{H2S}$ given sulfur is more electronegative, and most importantly why the same logic used in 1. can't be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated.

retag, format
Source Link

Assessing How to assess the strength of the acid?

Question: Which is the stronger acid in the given pairs?

Which is the stronger acid in the given pairs?

  1. $\ce{HClO3}$ and $\ce{HBrO3}$

  2. $\ce{HClO2}$ and $\ce{HClO}$

  3. $\ce{H2Se}$ and $\ce{H2S}$

My work:

  1. given that the # of oxygens is the same, the most electronegative atom should result in a stronger acid, thus $\ce{HCLO3}$ is stronger.

  2. $\ce{HCLO2}$ is stronger since it has more oxygen atoms.

  3. Here's where my logic fails, since the structure is the same (both have $\ce{2H+}$) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, Sulfursulfur is more electronegative thus stronger acid which was my original answer. But, the correct answer is $\ce{H2Se}$ is the stronger acid which implies in this case atomic size ($\ce{Se}$ is larger than $\ce{S}$) outweighs electronegativity. I dontdo not understand why in this case $\ce{H2Se}$ is stronger than $\ce{H2S}$ given Sulfursulfur is more electronegative, and most importantly why the same logic used in 1). can't be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated.

Assessing the strength of the acid

Question: Which is the stronger acid in the given pairs?

  1. $\ce{HClO3}$ and $\ce{HBrO3}$

  2. $\ce{HClO2}$ and $\ce{HClO}$

  3. $\ce{H2Se}$ and $\ce{H2S}$

My work:

  1. given that the # of oxygens is the same, the most electronegative atom should result in a stronger acid, thus $\ce{HCLO3}$ is stronger.

  2. $\ce{HCLO2}$ is stronger since it has more oxygen atoms.

  3. Here's where my logic fails, since the structure is the same (both have $\ce{2H+}$) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, Sulfur is more electronegative thus stronger acid which was my original answer. But, the correct answer is $\ce{H2Se}$ is the stronger acid which implies in this case atomic size ($\ce{Se}$ is larger than $\ce{S}$) outweighs electronegativity. I dont understand why in this case $\ce{H2Se}$ is stronger than $\ce{H2S}$ given Sulfur is more electronegative, and most importantly why the same logic used in 1) can't be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated

How to assess the strength of the acid?

Which is the stronger acid in the given pairs?

  1. $\ce{HClO3}$ and $\ce{HBrO3}$

  2. $\ce{HClO2}$ and $\ce{HClO}$

  3. $\ce{H2Se}$ and $\ce{H2S}$

  4. given that the # of oxygens is the same, the most electronegative atom should result in a stronger acid, thus $\ce{HCLO3}$ is stronger.

  5. $\ce{HCLO2}$ is stronger since it has more oxygen atoms.

  6. Here's where my logic fails, since the structure is the same (both have $\ce{2H+}$) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, sulfur is more electronegative thus stronger acid which was my original answer. But, the correct answer is $\ce{H2Se}$ is the stronger acid which implies in this case atomic size ($\ce{Se}$ is larger than $\ce{S}$) outweighs electronegativity. I do not understand why in this case $\ce{H2Se}$ is stronger than $\ce{H2S}$ given sulfur is more electronegative, and most importantly why the same logic used in 1. can't be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated.

Question: Which is the stronger acid in the given pairs?

  1. HCLO3 and HBrO3

    $\ce{HClO3}$ and $\ce{HBrO3}$

  2. $\ce{HClO2}$ and $\ce{HClO}$

  3. $\ce{H2Se}$ and $\ce{H2S}$

2)HCLO2 and HCLO

3)H2Se and H2S

My work:

  1. given that the # of oxygens is the same, the most electronegative atom should result in a stronger acid, thus HCLO3$\ce{HCLO3}$ is stronger.

  2. HCLO2$\ce{HCLO2}$ is stronger since it has more oxygen atoms.

  3. Here's where my logic fails, since the structure is the same  (both have 2 H+$\ce{2H+}$) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, Sulfur is more e-negativeelectronegative thus stronger acid which was my original answer. BUTBut, the correct answer is H2SE$\ce{H2Se}$ is the stronger acid which implies in this case atomic size  (Selenium$\ce{Se}$ is larger than Sulfur$\ce{S}$) outweighs electronegativity. I dont understand why in this case H2Se$\ce{H2Se}$ is stronger than H2S$\ce{H2S}$ given Sulfur is more electronegative, and most importantly why the same logic used in 1) cantcan't be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated

Question: Which is the stronger acid in the given pairs?

  1. HCLO3 and HBrO3

2)HCLO2 and HCLO

3)H2Se and H2S

My work:

  1. given that the # of oxygens is the same, the most electronegative atom should result in a stronger acid, thus HCLO3 is stronger

  2. HCLO2 is stronger since it has more oxygen atoms

  3. Here's where my logic fails, since the structure is the same(both have 2 H+) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, Sulfur is more e-negative thus stronger acid which was my original answer. BUT, the correct answer is H2SE is the stronger acid which implies in this case atomic size(Selenium is larger than Sulfur) outweighs electronegativity. I dont understand why in this case H2Se is stronger than H2S given Sulfur is more electronegative, and most importantly why the same logic used in 1) cant be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated

Question: Which is the stronger acid in the given pairs?

  1. $\ce{HClO3}$ and $\ce{HBrO3}$

  2. $\ce{HClO2}$ and $\ce{HClO}$

  3. $\ce{H2Se}$ and $\ce{H2S}$

My work:

  1. given that the # of oxygens is the same, the most electronegative atom should result in a stronger acid, thus $\ce{HCLO3}$ is stronger.

  2. $\ce{HCLO2}$ is stronger since it has more oxygen atoms.

  3. Here's where my logic fails, since the structure is the same  (both have $\ce{2H+}$) then it boils down to 2 things to account for: electronegativity and the size of the atom. Going with electronegativity, Sulfur is more electronegative thus stronger acid which was my original answer. But, the correct answer is $\ce{H2Se}$ is the stronger acid which implies in this case atomic size  ($\ce{Se}$ is larger than $\ce{S}$) outweighs electronegativity. I dont understand why in this case $\ce{H2Se}$ is stronger than $\ce{H2S}$ given Sulfur is more electronegative, and most importantly why the same logic used in 1) can't be applied here and how do I discern where to account for atomic size specifically or when to account for electronegativity?

Any detailed-dumbed down explanations on the logic are highly appreciated

Post Migrated Here from biology.stackexchange.com (revisions)
Source Link
Jx1
  • 435
  • 1
  • 6
  • 12
Loading