In organometallic chemistry, one of the most common ligands is the carbonyl. CO can bind to a single metal, or serve as a bridge between two or more metals.
In metal carbonyls complexes, a back-donation effect occurs: the sigmaσ molecular orbital of CO yields electron density to an orbital of the appropriate metal atom, and in turn, a d orbital of appropriate symmetry yields electron density to the anti-bonding piantibonding π* orbitals of CO.
On the basis of this model, the properties of carbonyls (e.g., the vibrational energy of the C-OC–O bond or its bond length) can be explained.
It is found that:
For example, in the following table, I would have to be able to explain these values onunderstand that all of the basisbond lengths are longer than in free CO, because of this backdonation which decreases the carbonyl retrodonation effectC–O bond order. However, but I really don't know very well how to approach it.can the differences between the three metal complexes be explained?
Species | C–O bond length (pm) |
---|---|
$\ce{CO}$ | 112.8 |
$\ce{[Ti(CO)6]^2+}$ | 116.0 |
$\ce{[Cr(CO)6]}$ | 114.0 |
$\ce{[Ni(CO)4]}$ | 113.0 |