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May 29, 2021 at 20:06 comment added Ashish I closed it under the wrong question by mistake since that doen't really answer it rather if I were to choose one I would say that it was the more similar to this chemistry.stackexchange.com/questions/40054/… please change it If it can be
May 29, 2021 at 20:05 history closed Mathew Mahindaratne
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Duplicate of Short Cut Method to Calculating pH of Polyprotic Acid?
May 29, 2021 at 20:04 comment added Ashish Acid Base reaction! My bad, I was considering it's dissociation as a WA in solution
May 29, 2021 at 19:45 comment added Poutnik @Ashish You do not expect strongly acidic H3PO4 and strongly alkalic PO4^3- can survive aside each other, do you ?
May 29, 2021 at 19:16 comment added Ashish Ok I read the question above and it starts with $\ce{H_2PO_4^-}$ and $\ce{HPO_4^{2-}}$ . I could use that in here but my doubt is that and also with comment made by @Poutnik The $Ka1$ of the acid is given as $10^{-5}$ so how can I assume that $\ce{H_3PO_4}$ is getting 100% dissociated into $\ce{H_2PO4^-}$
May 28, 2021 at 13:47 comment added Rishi @Ashish This helps chemistry.stackexchange.com/questions/40054/… ?
May 28, 2021 at 10:57 comment added Poutnik Correction 0.5 M + 0.5 M - simple error.
May 28, 2021 at 10:04 comment added Poutnik It would be 1 M NaH2PO4 + 1 M Na2HPO4 ( hydrolysis neglected), so pH=pKa2. ( simplification assuming activity coefficient is 1, what is expected in this task context, otherwise not really justified ). It is high concentration, buffers are usually much more diluted solutions, typically 0.05-0.1 M.
May 28, 2021 at 9:40 history edited Ashish CC BY-SA 4.0
added 118 characters in body
May 28, 2021 at 8:57 review Close votes
May 29, 2021 at 20:05
May 28, 2021 at 8:52 history edited Mathew Mahindaratne CC BY-SA 4.0
Improved formatting and clarity.
May 28, 2021 at 8:46 comment added Ashish @NisargBhavsar Oh, that makes sense. I understand why it's wrong now
May 28, 2021 at 8:43 comment added Ashish @MathewMahindaratne Doesn't seem to me like they are the same questions because it's hydrolysis is also to be considered in this case since the concentration of Na3PO4 is also given which is not taken in the linked question. Rather the linked question would answer my question if only the concentration of H3PO4 was provided to me
May 28, 2021 at 8:15 comment added Nisarg Bhavsar Your assumption that the phosphate ion will not hydrolyze makes your attempt incorrect. Final concentration of phosphate will not be equal to it's initial concentration.
May 28, 2021 at 8:02 history asked Ashish CC BY-SA 4.0