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Post Closed as "Duplicate" by Nilay Ghosh, Todd Minehardt, Mathew Mahindaratne, Jon Custer, CommunityBot
Improved formatting on chemical formulae and on electron configurations
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edit approved Jan 11, 2021 at 12:07
Lynn Gu
edit approved Jan 11, 2021 at 12:07
Lynn Gu
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The three more energy electron layers for Indium(49) are, sorted from lower to higher energy:

[Kr] 5s2 4d10 5p1$5\text{s}^24\text{d}^{10}5\text{p}^1$

From this configuration, it could be said that is easy to subtract the 5p1$5\text{p}^1$ electron (oxidation state +1), next start subtracting electrons from the 4d layer. However, the more common oxidation state of Indium is +3 (as in In2Se3$\ce{In2Se3}$). It seems electrons are subtractsubtracted from layer 5s before to the ones of 4d. This could break the rule of fillfilling the lower energy layer first.

How to explain the +3 oxidation state of Indium taken into account electron configurations  ?

The three more energy electron layers for Indium(49) are, sorted from lower to higher energy:

[Kr] 5s2 4d10 5p1

From this configuration, it could be said that is easy to subtract the 5p1 electron (oxidation state +1), next start subtracting electrons from 4d layer. However, the more common oxidation state of Indium is +3 (as in In2Se3). It seems electrons are subtract from layer 5s before to the ones of 4d. This could break the rule of fill lower energy layer first.

How to explain +3 oxidation state of Indium taken into account electron configurations  ?

The three more energy electron layers for Indium(49) are, sorted from lower to higher energy:

[Kr] $5\text{s}^24\text{d}^{10}5\text{p}^1$

From this configuration, it could be said that is easy to subtract the $5\text{p}^1$ electron (oxidation state +1), next start subtracting electrons from the 4d layer. However, the more common oxidation state of Indium is +3 (as in $\ce{In2Se3}$). It seems electrons are subtracted from layer 5s before to the ones of 4d. This could break the rule of filling the lower energy layer first.

How to explain the +3 oxidation state of Indium taken into account electron configurations?

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The three more energy electron layers for Indium(49) are, sorted from lower to higher energy:

[Kr] 5s2 4d10 5p1

From this configuration, it could be said that is easy to subtract 1the 5p1 electron (oxidation state +1), next start subtracting electrons from 4d layer. However, the more common oxidation state of Indium is +3 (as in In2Se3). It seems electrons are subtract from layer 5s before to the ones of 4d. This could break the rule of fill lower energy layer first.

How to explain +3 oxidation state of Indium taken into account electron configurations ?

The three more energy electron layers for Indium(49) are, sorted from lower to higher energy:

[Kr] 5s2 4d10 5p1

From this configuration, it could be said that is easy to subtract 1 electron (oxidation state +1), next start subtracting electrons from 4d layer. However, the more common oxidation state of Indium is +3 (as in In2Se3). It seems electrons are subtract from layer 5s before to the ones of 4d. This could break the rule of fill lower energy layer first.

How to explain +3 oxidation state of Indium taken into account electron configurations ?

The three more energy electron layers for Indium(49) are, sorted from lower to higher energy:

[Kr] 5s2 4d10 5p1

From this configuration, it could be said that is easy to subtract the 5p1 electron (oxidation state +1), next start subtracting electrons from 4d layer. However, the more common oxidation state of Indium is +3 (as in In2Se3). It seems electrons are subtract from layer 5s before to the ones of 4d. This could break the rule of fill lower energy layer first.

How to explain +3 oxidation state of Indium taken into account electron configurations ?

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Why is +3 the oxidation state of Indium?

The three more energy electron layers for Indium(49) are, sorted from lower to higher energy:

[Kr] 5s2 4d10 5p1

From this configuration, it could be said that is easy to subtract 1 electron (oxidation state +1), next start subtracting electrons from 4d layer. However, the more common oxidation state of Indium is +3 (as in In2Se3). It seems electrons are subtract from layer 5s before to the ones of 4d. This could break the rule of fill lower energy layer first.

How to explain +3 oxidation state of Indium taken into account electron configurations ?