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Q.15 the major product of the following reaction is:

 

enter image description here

I have read that $\ce{NaBH4}$ reduces only aldehyde, ketone and acid chlorides. In some cases it may reduce double bonds conjugated with carbonyl groups. So shouldn't the answer here be option 1?

Q.15 the major product of the following reaction is:

 

enter image description here

I have read that $\ce{NaBH4}$ reduces only aldehyde, ketone and acid chlorides. In some cases it may reduce double bonds conjugated with carbonyl groups. So shouldn't the answer here be option 1?

Q.15 the major product of the following reaction is:

enter image description here

I have read that $\ce{NaBH4}$ reduces only aldehyde, ketone and acid chlorides. In some cases it may reduce double bonds conjugated with carbonyl groups. So shouldn't the answer here be option 1?

added 82 characters in body; edited tags; edited title
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andselisk
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Does $\ce {NaBH_4}$sodium borohydride reduce $C=N $C=N group?

enter image description here

Q.15 the major product of the following reaction is:

enter image description here

I have read that $\ce {NaBH_4}$$\ce{NaBH4}$ reduces only aldehyde,ketone ketone and acid chlorides. In some cases it may reduce double bonds conjugated with carbonyl groups. So shouldn't the answer here be option 11?

Does $\ce {NaBH_4}$ reduce $C=N $ group?

enter image description here

I have read that $\ce {NaBH_4}$ reduces only aldehyde,ketone and acid chlorides. In some cases it may reduce double bonds conjugated with carbonyl groups. So shouldn't the answer here be option 1?

Does sodium borohydride reduce C=N group?

Q.15 the major product of the following reaction is:

enter image description here

I have read that $\ce{NaBH4}$ reduces only aldehyde, ketone and acid chlorides. In some cases it may reduce double bonds conjugated with carbonyl groups. So shouldn't the answer here be option 1?

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Soham
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Does $\ce {NaBH_4}$ reduce $C=N $ group?

enter image description here

I have read that $\ce {NaBH_4}$ reduces only aldehyde,ketone and acid chlorides. In some cases it may reduce double bonds conjugated with carbonyl groups. So shouldn't the answer here be option 1?