My question is due to a discrepancy I founnd in reactivity and organic conversions. In reactivity of organic compounds it has been established that an alkyl group activates the benzene ring and hence for example:

-methylbenzene is more reactive than benzene

then consider the following situation.

  Suppose that there are 2 benzene molecules in a sample and we convert one of them to toluene(methylbenzene) using Friedel–Crafts alkylation. Then we would see the following change in the mixture:  

Now consider we carry out alkylation once more. Now as Toluene is more reactive than benzene it will react first forming di-methylbenzene. By continuing this logic we would get hexa-methylbenzene as the major product regardless of the number of moles we add.

So how is that we carry out conversions with Friedel–Crafts alkylation regarding toluene as the major product?

[Feel free to correct me if my logic is incorrect and if so please specify what should be corrected]

My question is due to a discrepancy I found in reactivity and organic conversions. In reactivity of organic compounds it has been established that an alkyl group activates the benzene ring, and, hence for example, methylbenzene is more reactive than benzene.

Then consider the following situation. Suppose that there are two benzene molecules in a sample, and we convert one of them to toluene  (methylbenzene) using Friedel–Crafts alkylation. Then we would see the following change in the mixture: 

Now, consider we carry out alkylation once more. As toluene is more reactive than benzene, it will react first forming dimethylbenzene. By continuing this logic we would get hexamethylbenzene as the major product regardless of the amounts we add.

So, how is that we carry out conversions with Friedel–Crafts alkylation regarding toluene as the major product?

Feel free to correct me if my logic is incorrect and if so please specify what should be corrected.

My question is due to a discreency I founnd in reactivity and organic conversions. In reactivity of organic compounds it has been established that an alkyl group activates the benzene ring and hence for example:

-methylbenzene is more reactive than benzene

then consider the following situation.

Suppose that there are 2 benzene molecules in a sample and we convert one of them to toluene(methylbenzene) using friedal craft alkylation. Then we would see the following change in the mixture:

Now consider we carry out alkylation once more. Now as Toluene is more reactive than benzene it will react first forming di-methylbenzene. By continuing this logic we would get hexa-methylbenzene as the major product regardless of the number of moles we add.

So how is that we carry out conversions with friedal craft alkylation regarding toluene as the major product?

[Feel free to correct me if my logic is incorrect and if so please specify what should be corrected]

My question is due to a discrepancy I founnd in reactivity and organic conversions. In reactivity of organic compounds it has been established that an alkyl group activates the benzene ring and hence for example:

-methylbenzene is more reactive than benzene

then consider the following situation.

Suppose that there are 2 benzene molecules in a sample and we convert one of them to toluene(methylbenzene) using Friedel–Crafts alkylation. Then we would see the following change in the mixture:

Now consider we carry out alkylation once more. Now as Toluene is more reactive than benzene it will react first forming di-methylbenzene. By continuing this logic we would get hexa-methylbenzene as the major product regardless of the number of moles we add.

So how is that we carry out conversions with Friedel–Crafts alkylation regarding toluene as the major product?

[Feel free to correct me if my logic is incorrect and if so please specify what should be corrected]