I have some HF... I am thinking of trying this with proper precautions in a fume hood, etc. After a while at room temperature I could expect SiO2 granules should shoe some kind of disintegration? I was under the impression that Al2O3 would also react with HF.

Ok I think that this is about right. It at least kind of convinces me for the moment... I am coming from a physics background so this electrochemistry stuff has had my head spinning.

Ok So I did a few calculations that get me close to the number in the paper and I am wondering if this is the right direction. 144.1 mol of electrons is $8.7 \times 10^{25}$ electrons. Assuming that the cell for this lithium ion battery is 3.2 volts then it would take 3.2eV to bring one electron through this potential. So 3.2 eV * $8.7 \times 10^{25}$ electrons = $2.8 \times 10^{26}$. Then converting eV to Wh I see that 1 eV = $4.45 \times 10^{-23}$. This is 12388.8 Wh/kg. Perhaps they assume that they are working with a lower voltage cell to get the lower number? Does this look right?

Ahhh thank you! That certainly makes a lot more sense. So using that I could say that 1 kg of $Li^{+}$ is 144.1 mol of $Li^{+} $ Which would produce 144.1 mol of electrons right? So I guess where I am confused is how to go from there to the Wh/kg which is a unit of energy. I guess you would have to know the voltage of the cell that the electrons would be crossing and use that potential difference to try to get to energy?