I have no idea how to determine the substituents on the aromatic ring from NMR diagram. There is (might be ) a triplet on my NMR around 7.59-7.65ppm which has 4 hydrogens in the same environment. If so, there must be two ortho substituents on two aromatic rings but I think the 4 Hs won't be in the same environment. Someone can help me ? Thank you very much!