I am trying to do the following problem:
Freezing of water at 273 K and 1 atm
Which of the following is true for the above thermodynamics process?
p) q=0
q) w=0
r) ΔSsys<0
s) ΔU=0
t) ΔG=0
My answer was r, s, and t:
- Since the reaction happens at constant temperature, internal energy is constant (yes for s)
- Since the reaction is open, it is isobaric in nature; and since the volume changes due to the phase change the work done is not zero (no for q)
- Heat must be exchanged (first law of thermodynamics) (no for p)
- Randomness decreases so ΔSsys<0 (yes for r)
But, the answer given is q, r, and t. I don't understand why q is correct but s is not.