Are $K_P$ and $K_C$ dependent on initial concentration of reactants? So far I had known that $K_P$ and $K_C$ are only dependent on temperature which is explained by thermydnamic approaches perhaps. I didn't learn the derivations of those equilibrium constants. I just learnt that they are the ratio of product of active masses of respective products and reactants. But I am asking this question because I was stuck at a point while solving a problem regarding $K_P$ and $K_C$
The problem:
In the dissociation reaction of Nitrogen tetraoxide$(N_2O_4)$ $100\alpha$% of the reactant is dissociated at $P atm$ pressure and at $TK$ temperature[suppose volume=$V$]
so as per the problem if the initial concentration of the reactant is $C M$ then concentration of product is $\alpha C M$ at equilibrium $$N_2O_4<=>2NO_2$$ $$initial:C <=>0 $$ $$equilibrium:C-C\alpha<=>2C\alpha$$
so $$K_C=\frac{[NO_2]^2} {[N_2O_4]}=\frac{4C^2\alpha^2} {C(1-\alpha)}=\frac{4C\alpha^2} {(1-\alpha)}$$ $$K_P=\frac{P_{(NO_2)}^2} {P{(N_2O_4)}^2}=\frac{\frac{4C^2P^2\alpha^2V^2} {CV(1-\alpha)+2CV\alpha}} {\frac{CPV(1-\alpha)} {CV(1-\alpha)+2CV\alpha}}=\frac{4P\alpha^2} {(1-\alpha)}$$
so It can be seen that in the equation of $K_C$ there is $C$ involved in the numerator. since equilibrium constants are not dependent on intial concentration, I suppose that the degree of dissociation($\alpha$) varies depending on initial conditions. But if $\alpha$ changes depending on intial concentration does not that make $K_P$ dependent on intial concentration? Where am I wrong here?
Thank you.