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Mithoron
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Which compundcompound is responsible for the Borax Bead Testborax bead test?

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Avyansh Katiyar
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When borax is heated, the reaction that takes place is :

$$Na_2B_4O_7.10H_2O \ce{->} 2NaBO_2 + B_2O_3 + 10H_2O$$$$\ce{Na_2B_4O_7.10H_2O \ce{->} 2NaBO_2 + B_2O_3 + 10H_2O}$$ And the compounds that are responsible for the colors are $M_x(BO_2)_y$$\ce{M_x(BO_2)_y}$ salts, like $Co(BO_2)_2$$\ce{Co(BO_2)_2}$. My question is, does this $BO_2$$\ce{BO_2}$ come from $NaBO_2$$\ce{NaBO_2}$ or from $B_2O_3$$\ce{B_2O_3}$ or do both of them react?

When borax is heated, the reaction that takes place is :

$$Na_2B_4O_7.10H_2O \ce{->} 2NaBO_2 + B_2O_3 + 10H_2O$$ And the compounds that are responsible for the colors are $M_x(BO_2)_y$ salts, like $Co(BO_2)_2$. My question is, does this $BO_2$ come from $NaBO_2$ or from $B_2O_3$ or do both of them react?

When borax is heated, the reaction that takes place is :

$$\ce{Na_2B_4O_7.10H_2O \ce{->} 2NaBO_2 + B_2O_3 + 10H_2O}$$ And the compounds that are responsible for the colors are $\ce{M_x(BO_2)_y}$ salts, like $\ce{Co(BO_2)_2}$. My question is, does this $\ce{BO_2}$ come from $\ce{NaBO_2}$ or from $\ce{B_2O_3}$ or do both of them react?

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dryairship
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Which compund is responsible for the Borax Bead Test?

When borax is heated, the reaction that takes place is :

$$Na_2B_4O_7.10H_2O \ce{->} 2NaBO_2 + B_2O_3 + 10H_2O$$ And the compounds that are responsible for the colors are $M_x(BO_2)_y$ salts, like $Co(BO_2)_2$. My question is, does this $BO_2$ come from $NaBO_2$ or from $B_2O_3$ or do both of them react?