Timeline for Addition Reaction
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 13, 2018 at 20:24 | comment | added | user55119 | The point of the "impure ether" is to imply that the hydroperoxide is present and that the radical Kharasch Reaction (anti-Markovnikov) is faster than the ionic, Markovnikov process. When Kharasch used peroxide-free ether, the ionic route prevailed. | |
| Feb 13, 2018 at 6:45 | comment | added | Apoorv Potnis | @Gaurang What I want to suggest is that diethyl ether gets converted diethyl ether peroxide (impure $\ce{Et2O}$) and then as peroxide bond is weak, it can be broken easily and the reaction can proceed via free radical mechanism. | |
| Feb 13, 2018 at 5:12 | comment | added | Gaurang Tandon | @ApoorvPotnis Re: "\ce{O-O} bond in peroxides" as Sarah Smith noted, I don't see why you're bringing in peroxides into the question. Yes, the solution mentions diethyl ether peroxide (to which you later linked) but there doesn't seem to be any immediate connection to the question. Quoting Sarah Smith again, "Is there any way to know that there is a peroxide in the reaction just from looking at the first image?" Please consider elaborating. Thank you! | |
| Feb 7, 2018 at 8:29 | history | tweeted | twitter.com/StackChemistry/status/961154935453872129 | ||
| Feb 7, 2018 at 4:44 | comment | added | Avyansh Katiyar | impure is there | |
| Feb 7, 2018 at 4:42 | comment | added | Apoorv Potnis | See this. | |
| Feb 7, 2018 at 4:37 | comment | added | Sarah Smith | Thank you. The first image is the question (which is asking us to draw the mechanism) while the second image is the answer. However, I believe the first image does not indicate that there is a peroxide in the reaction. Is there any way to know that there is a peroxide in the reaction just from looking at the first image? | |
| Feb 7, 2018 at 4:34 | comment | added | Apoorv Potnis | The $\ce{O-O}$ bond in peroxides is weak $(\Delta H^{\circ} = 150~\pu{kJ} = 36~\pu{kcal})$. So, slight heating can break the peroxy bond. And radicals are very reactive species. | |
| Feb 7, 2018 at 4:14 | history | asked | Sarah Smith | CC BY-SA 3.0 |