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Add negative charge sign to second equation, reactant side (charge balance was incorrect as written).
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edit approved Jul 22, 2015 at 0:46
Todd Minehardt
edit approved Jul 22, 2015 at 0:46
Todd Minehardt
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Does flipping a reaction as written change the sign of the value of E or is it a completely different value?

For example if I have the value for the half reaction $\ce{Cl2 + 2e- -> 2Cl-}$ but need the value for the opposite reaction ($\ce{2Cl -> Cl2 + 2e-}$$\ce{2Cl- -> Cl2 + 2e-}$), do I just put a negative sign and treat it like $\Delta H$ values?

Does flipping a reaction change the sign of the value of E or is it a completely different value?

For example if I have the value for the half reaction $\ce{Cl2 + 2e- -> 2Cl-}$ but need the value for the opposite reaction ($\ce{2Cl -> Cl2 + 2e-}$), do I just put a negative sign and treat it like $\Delta H$ values?

Does flipping a reaction as written change the sign of the value of E or is it a completely different value?

For example if I have the value for the half reaction $\ce{Cl2 + 2e- -> 2Cl-}$ but need the value for the opposite reaction ($\ce{2Cl- -> Cl2 + 2e-}$), do I just put a negative sign and treat it like $\Delta H$ values?

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ron
ron
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Does flipping a reaction change the sign of the value of E or is it a completely different value?

For example if I have the value for the half reaction Cl2 + 2e- --> 2Cl-$\ce{Cl2 + 2e- -> 2Cl-}$ but need the value for the opposite reaction (2Cl -> Cl2 + 2e-$\ce{2Cl -> Cl2 + 2e-}$), do I just put a negative sign and treat it like delta H$\Delta H$ values?

Does flipping a reaction change the sign of the value of E or is it a completely different value?

For example if I have the value for the half reaction Cl2 + 2e- --> 2Cl- but need the value for the opposite reaction (2Cl -> Cl2 + 2e-), do I just put a negative sign and treat it like delta H values?

Does flipping a reaction change the sign of the value of E or is it a completely different value?

For example if I have the value for the half reaction $\ce{Cl2 + 2e- -> 2Cl-}$ but need the value for the opposite reaction ($\ce{2Cl -> Cl2 + 2e-}$), do I just put a negative sign and treat it like $\Delta H$ values?

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user16949
user16949
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Electrode Potential Half Reactions

Does flipping a reaction change the sign of the value of E or is it a completely different value?

For example if I have the value for the half reaction Cl2 + 2e- --> 2Cl- but need the value for the opposite reaction (2Cl -> Cl2 + 2e-), do I just put a negative sign and treat it like delta H values?