Timeline for Why are solids and liquids not included in the equilibrium constant? What about in a reaction rate calculation?
Current License: CC BY-SA 3.0
14 events
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Feb 24, 2018 at 11:16 | history | edited | Gaurang Tandon | CC BY-SA 3.0 |
what was the need of italics?+mathcal->normal R
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Apr 18, 2017 at 8:26 | comment | added | Martin - マーチン♦ | @Freelancer If you have another question, please ask it by clicking the Ask Question button. As I stated: "in the standard definition all compounds regardless of their state are included in the equilibrium." | |
Apr 18, 2017 at 8:23 | comment | added | Freelancer | But the liquids are not included in equilibrium constant ... So as all reactants and products are liquids then none of them will be included in equilibrium constant so whose concentration will we use while writing the equilibrium constant ? | |
Apr 18, 2017 at 8:12 | comment | added | Martin - マーチン♦ | @Freelancer As long as it is in equilibrium: Yes. | |
Apr 18, 2017 at 8:06 | comment | added | Freelancer | Then what will be the equilibrium constant of a reaction in which all the reactants and products are say liquid will such a reaction have any equilibrium constant ? | |
Jul 2, 2014 at 7:43 | comment | added | Martin - マーチン♦ | @Greg I hope my edit fixes this. | |
Jul 2, 2014 at 7:43 | history | edited | Martin - マーチン♦ | CC BY-SA 3.0 |
added 296 characters in body
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Jul 2, 2014 at 7:37 | comment | added | Greg | It is not true. The reaction is both direction will scale with the surface, therefore the it will not appear in the equilibrium constant. | |
Jul 2, 2014 at 6:12 | comment | added | Martin - マーチン♦ | There is! Tabulated are mostly standard values at standard temperature and pressure. Have a look at the second definition and you will see the temperature dependency of $K$. | |
Jul 2, 2014 at 6:04 | comment | added | 1110101001 | However, for the equilibrium expression if the solids and liquids are considered constants because their "concentration" is dependent on their partial pressures, wouldn't changing the temperature change the partial pressure and thus their "concentration"? So then why isn't their different equilibrium constants for different temperatures? | |
Jul 2, 2014 at 5:54 | vote | accept | 1110101001 | ||
Jul 2, 2014 at 5:36 | comment | added | Martin - マーチン♦ | Yes you are correct. As long as the surface does not change, everything related to it is constant and can be included in the rate constant. | |
Jul 2, 2014 at 4:33 | comment | added | 1110101001 | So from what I understand, solids and liquids are considered to be constants because their "concentration" depends on their partial pressure which is independent of the amount present, right? And for the rate expression it is also ignored for the same reason and any effects due to surface area are included in the rate constant? | |
Jul 2, 2014 at 3:49 | history | answered | Martin - マーチン♦ | CC BY-SA 3.0 |