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Jun 2, 2022 at 3:27 history edited andselisk CC BY-SA 4.0
deleted 112 characters in body; edited tags
May 22, 2019 at 11:16 answer added Mayuri Vaish timeline score: 3
S May 21, 2019 at 12:36 history suggested Ian Bush
Removed irrelevant tag
May 21, 2019 at 12:34 review Suggested edits
S May 21, 2019 at 12:36
May 21, 2019 at 12:09 comment added Mayuri Vaish @Poutnik I got it!!! Thank you!!! Essentially, both reactions involving Cu+ have the lowest and highest SEPs respectively - so they have to be the strongest oxidizing/reducing agents - thus undergoing disproportionation. :)))
May 21, 2019 at 11:38 comment added Poutnik Take it as if Cu(I) had been 2 different compounds in one. One as oxidizing agent, the other as reduction agent. Compare potentials for their half reaction.
May 21, 2019 at 11:23 comment added Nilay Ghosh Strongly related; chemistry.stackexchange.com/questions/42855/…
May 21, 2019 at 11:13 comment added Poutnik as they are directly related to delta G via nF factor.
May 21, 2019 at 11:04 comment added Poutnik Did you compare standard potentials of all 3 half reactions ?
May 21, 2019 at 11:02 comment added Mayuri Vaish @Poutnik - thanks, yes I did. But that does not explain why in terms of the standard electrode potentials involved. I'm having a hard time understanding how you could infer that from the SEPs given. Do you have any idea? Thanks in advance.!
May 21, 2019 at 10:56 comment added Poutnik See related chemistry.stackexchange.com/questions/115660/…
May 21, 2019 at 10:52 history edited andselisk CC BY-SA 4.0
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May 21, 2019 at 10:47 history asked Mayuri Vaish CC BY-SA 4.0