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I was asked to draw all possible stereoisomers of inositol (1,2,3,4,5,6-cyclohexanehexol). To obtain the answer I had to assume that all six carbons of the molecule are asymmetric, which (bearing in mind possible molecular symmetry) results on the following nine stereoisomers:1[1]

InositolIsomersInositolIsomers

The problem is that I fail to see why these carbons can be considered chiral centers. Given:[2]

"TheThe most common cause of chirality in an organic molecule, although not the only one, is the presence of a carbon atom bonded to four different groups [...]. These carbons are now named chiral centers [...]" 1]

The chirality of the molecule is not the reason of my doubts, I can see that the only chiral isomers are D- and L- chiro-inositol. Since all carbons in the ring possess a hydroxyl group, can they not be considered to be bonded to equivalent substituents, making them symmetric? Is the possibility of the -OH groups to be above or below the plane of the ring what makes them asymmetric?

1: From Wikipedia
[2]: McMurry, John. Organic Chemistry. CENGAGE Learning, 2008. 7th edition.

  1. From Wikipedia
  2. McMurry, John. Organic Chemistry. CENGAGE Learning, 2008. 7th edition.

I was asked to draw all possible stereoisomers of inositol (1,2,3,4,5,6-cyclohexanehexol). To obtain the answer I had to assume that all six carbons of the molecule are asymmetric, which (bearing in mind possible molecular symmetry) results on the following nine stereoisomers:1

InositolIsomers

The problem is that I fail to see why these carbons can be considered chiral centers. Given:

"The most common cause of chirality in an organic molecule, although not the only one, is the presence of a carbon atom bonded to four different groups [...]. These carbons are now named chiral centers [...]" 1

The chirality of the molecule is not the reason of my doubts, I can see that the only chiral isomers are D- and L- chiro-inositol. Since all carbons in the ring possess a hydroxyl group, can they not be considered to be bonded to equivalent substituents, making them symmetric? Is the possibility of the -OH groups to be above or below the plane of the ring what makes them asymmetric?

1: From Wikipedia
[2]: McMurry, John. Organic Chemistry. CENGAGE Learning, 2008. 7th edition.

I was asked to draw all possible stereoisomers of inositol (1,2,3,4,5,6-cyclohexanehexol). To obtain the answer I had to assume that all six carbons of the molecule are asymmetric, which (bearing in mind possible molecular symmetry) results on the following nine stereoisomers:[1]

InositolIsomers

The problem is that I fail to see why these carbons can be considered chiral centers. Given:[2]

The most common cause of chirality in an organic molecule, although not the only one, is the presence of a carbon atom bonded to four different groups [...]. These carbons are now named chiral centers [...]

The chirality of the molecule is not the reason of my doubts, I can see that the only chiral isomers are D- and L- chiro-inositol. Since all carbons in the ring possess a hydroxyl group, can they not be considered to be bonded to equivalent substituents, making them symmetric? Is the possibility of the -OH groups to be above or below the plane of the ring what makes them asymmetric?

  1. From Wikipedia
  2. McMurry, John. Organic Chemistry. CENGAGE Learning, 2008. 7th edition.
be careful with capitalisation and spelling and don't use spanish question style
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Mithoron
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I was asked to draw all possible stereoisomers of Inositolinositol (1,2,3,4,5,6-cyclohexanehexol). To obtain the answer I had to assume that all six carbons of the molecule are asymmetric, which (bearing in mind possible molecular symmetry) results on the following nine stereoisomers:1

InositolIsomers

The problem is that I fail to see why these carbons can be considered chiral centers. Given:

"The most common cause of quiralitychirality in an organic molecule, altoughalthough not the only one, is the presence of a carbon atom bonded to four different groups [...]. These carbons are now named chiral centers [...]" 1

The chirality of the molecule is not the reason of my doubts, I can see that the only chiral isomers are D- and L- chiroinositolchiro-inositol. Since all carbons in the ring possess a hydroxilhydroxyl group, ¿cancan they not be considered to be bonded to equivalent substituents, making them symmetric? ¿IsIs the possibility of the -OH groups to be above or below the plane of the ring what makes them assymetricasymmetric?

1: From Wikipedia
[2]: McMurry, John. Organic Chemistry. CENGAGE Learning, 2008. 7th edition.

I was asked to draw all possible stereoisomers of Inositol (1,2,3,4,5,6-cyclohexanehexol). To obtain the answer I had to assume that all six carbons of the molecule are asymmetric, which (bearing in mind possible molecular symmetry) results on the following nine stereoisomers:1

InositolIsomers

The problem is that I fail to see why these carbons can be considered chiral centers. Given:

"The most common cause of quirality in an organic molecule, altough not the only one, is the presence of a carbon atom bonded to four different groups [...]. These carbons are now named chiral centers [...]" 1

The chirality of the molecule is not the reason of my doubts, I can see that the only chiral isomers are D- and L- chiroinositol. Since all carbons in the ring possess a hydroxil group, ¿can they not be considered to be bonded to equivalent substituents, making them symmetric? ¿Is the possibility of the -OH groups to be above or below the plane of the ring what makes them assymetric?

1: From Wikipedia
[2]: McMurry, John. Organic Chemistry. CENGAGE Learning, 2008. 7th edition.

I was asked to draw all possible stereoisomers of inositol (1,2,3,4,5,6-cyclohexanehexol). To obtain the answer I had to assume that all six carbons of the molecule are asymmetric, which (bearing in mind possible molecular symmetry) results on the following nine stereoisomers:1

InositolIsomers

The problem is that I fail to see why these carbons can be considered chiral centers. Given:

"The most common cause of chirality in an organic molecule, although not the only one, is the presence of a carbon atom bonded to four different groups [...]. These carbons are now named chiral centers [...]" 1

The chirality of the molecule is not the reason of my doubts, I can see that the only chiral isomers are D- and L- chiro-inositol. Since all carbons in the ring possess a hydroxyl group, can they not be considered to be bonded to equivalent substituents, making them symmetric? Is the possibility of the -OH groups to be above or below the plane of the ring what makes them asymmetric?

1: From Wikipedia
[2]: McMurry, John. Organic Chemistry. CENGAGE Learning, 2008. 7th edition.

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Why are carbons of Inositol chiral centers?

I was asked to draw all possible stereoisomers of Inositol (1,2,3,4,5,6-cyclohexanehexol). To obtain the answer I had to assume that all six carbons of the molecule are asymmetric, which (bearing in mind possible molecular symmetry) results on the following nine stereoisomers:1

InositolIsomers

The problem is that I fail to see why these carbons can be considered chiral centers. Given:

"The most common cause of quirality in an organic molecule, altough not the only one, is the presence of a carbon atom bonded to four different groups [...]. These carbons are now named chiral centers [...]" 1

The chirality of the molecule is not the reason of my doubts, I can see that the only chiral isomers are D- and L- chiroinositol. Since all carbons in the ring possess a hydroxil group, ¿can they not be considered to be bonded to equivalent substituents, making them symmetric? ¿Is the possibility of the -OH groups to be above or below the plane of the ring what makes them assymetric?

1: From Wikipedia
[2]: McMurry, John. Organic Chemistry. CENGAGE Learning, 2008. 7th edition.