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Apr 25, 2018 at 18:30 comment added user55119 I would argue that bond polarity has more to do with it. In Markovnikov's studies, he dealt with HX addition where H was always more positive than X. In the B-H bond, boron is more positive than H. Thus, I would classify the lefthand TS as Markovnikov-type addition. After the alkylborane oxidation, where O replaces B, the net result is anti-Markovnikov addition of water.
Apr 14, 2018 at 1:42 history edited Avyansh Katiyar
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Apr 14, 2018 at 0:42 comment added George Tian @orthocresol Done
Apr 14, 2018 at 0:41 history edited George Tian CC BY-SA 3.0
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Apr 14, 2018 at 0:22 comment added orthocresol Yes, you are correct. This would also be more helpful to future readers if you were to cite the textbook and a page number
Apr 14, 2018 at 0:13 history asked George Tian CC BY-SA 3.0