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basseur
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Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter is converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is what must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/s^2 = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (precision of 0.0001 g) in our lab that occasionally has the same problems. Sometimes I would measure an empty reaction flask and it would be fine but some other time I could watch the measured weight drop by the second, "losing" up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter is converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/s^2 = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (precision of 0.0001 g) in our lab that occasionally has the same problems. Sometimes I would measure an empty reaction flask and it would be fine but some other time I could watch the measured weight drop by the second, "losing" up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter is converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is what must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/s^2 = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (precision of 0.0001 g) in our lab that occasionally has the same problems. Sometimes I would measure an empty reaction flask and it would be fine but some other time I could watch the measured weight drop by the second, "losing" up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

typo corrected
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basseur
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Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter itis converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/(s^2) = 1.798\cdot10^{14}~J$$$$ E = 1.798\cdot10^{14} (kg~m^2)/s^2 = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (precision of 0.0001 g) in our lab that occasionally has the same problems. Sometimes I would measure an empty reaction flask and it would be fine but some other time I could watch the measured weight drop by the second, "losing" up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter it converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/(s^2) = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (precision of 0.0001 g) in our lab that occasionally has the same problems. Sometimes I would measure an empty reaction flask and it would be fine but some other time I could watch the measured weight drop by the second, "losing" up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter is converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/s^2 = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (precision of 0.0001 g) in our lab that occasionally has the same problems. Sometimes I would measure an empty reaction flask and it would be fine but some other time I could watch the measured weight drop by the second, "losing" up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

language correction
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basseur
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Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter it converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/(s^2) = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (weighing accuracyprecision of 0.0001 g) in our lab that occasionally has the same problems. Sometimes I would measure an empty reaction flask and at one time it would be fine but anothersome other time I could watch the measured weight drop by the second, "losing" sometimes up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter it converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/(s^2) = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (weighing accuracy of 0.0001 g) in our lab that occasionally has the same problems. I would measure an empty reaction flask and at one time it would be fine but another time I could watch the measured weight drop by the second, "losing" sometimes up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

Because collagen does not react with water and you say, no (measurable) evaporation of water is evident, there are only two options as to what is happening:

  1. Matter it converted into energy: If virtually no evaporation or spillage took place, and your scale is working properly, this is must have happened. Using the formula of mass-energy equivalence $E=mc^2$ (E = energy, m = mass, c = speed of light in a vacuum) we can calculate the amount of energy that should result from a "loss" of 2 grams: $$ E = 0.002~kg\cdot(2.998\cdot10^8~m/s)^2 $$ $$ E = 0.002~kg\cdot8.988\cdot10^{16}~m^2/s^2 $$ $$ E = 1.798\cdot10^{14} (kg~m^2)/(s^2) = 1.798\cdot10^{14}~J$$ so... that would be a LOT of energy.

  2. Your scale is not working as intended.

I'd go with option 2.

Now on a serious note: We do have a scale (precision of 0.0001 g) in our lab that occasionally has the same problems. Sometimes I would measure an empty reaction flask and it would be fine but some other time I could watch the measured weight drop by the second, "losing" up to 100 mg. The scale was checked by a professional but he could not find anything wrong with it.

My advice is: try another scale, see if the problem persists.

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basseur
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basseur
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