Timeline for Reason for the greater energy of the eclipsed conformer of alkanes?
Current License: CC BY-SA 3.0
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| Sep 29, 2017 at 14:20 | comment | added | Zhe | It's a little hard to parse what you mean. The classical picture doesn't matter because electron-electron repulsion is still defined in the same way. The electrons are overall closer in the eclipsed versus the staggered conformation. Not sure why you need to invoke breaking up the molecule. Increased repulsion increases energy. | |
| Sep 29, 2017 at 13:31 | comment | added | Inkjet | The way I think of the two electron system is that the potential energy content is higher once we push them together is that that is the energy needed to set up the closer configuration on bringing the charges from infinite separation to the closer separation, which is the classical picture of potential energy of a system. While your answer does give insight, do you essentially mean that the molecule tries to push the electrons together so has greater energy? Which is what I asked, my question remains, am I correct in thinking the way I did? | |
| Sep 29, 2017 at 11:50 | history | answered | Zhe | CC BY-SA 3.0 |