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Apr 24, 2020 at 23:38 comment added Zenix @M.A.R. I loved the edit summary ;)
Aug 18, 2019 at 20:55 answer added C.X.F. timeline score: 8
S Dec 30, 2018 at 7:02 history bounty ended CommunityBot
S Dec 30, 2018 at 7:02 history notice removed CommunityBot
Dec 22, 2018 at 11:32 history edited M.A.R. CC BY-SA 4.0
I just had some time on my hands
S Dec 22, 2018 at 5:57 history bounty started Jan
S Dec 22, 2018 at 5:57 history notice added Jan Draw attention
Jan 8, 2018 at 17:02 comment added Zhe If you go with Walsh cyclopropane, then there is a $p$-orbital right there. e.g., bluffton.edu/homepages/facstaff/bergerd/chem/walsh/derive.html
Jan 8, 2018 at 16:21 comment added orthocresol Agree with ron. The analogy to compound 1 I expected was trimethylenecyclopropane.
Jan 8, 2018 at 16:20 history edited orthocresol
edited tags
Aug 23, 2017 at 18:14 comment added ron As to the "proper alignment", see here
Aug 23, 2017 at 18:11 comment added ron Cyclopropane often acts like a double bond in terms of stabilizing adjacent positive charge, when the 3-membered ring is properly aligned. I've never see it discussed in the sense you suggest (removing one cyclopropane $\ce{CH2}$ group and then enlarging the other ring to include the remaining $\ce{CH2}$ group). The appropriate analogy would be to replace the cyclopropane with an exo-methylene type of double bond (e.g. removing one of the cyclopropane $\ce{CH2}$ groups and creating a double bond between the remaining $\ce{CH2}$ group and the former spiro-carbon).
Aug 23, 2017 at 17:03 history edited andselisk CC BY-SA 3.0
Fixed typos, adjusted benzene molecule
Aug 23, 2017 at 12:29 comment added Mithoron related chemistry.stackexchange.com/questions/33602/…
Aug 23, 2017 at 6:36 history tweeted twitter.com/StackChemistry/status/900245221652541441
Aug 23, 2017 at 2:52 history asked andselisk CC BY-SA 3.0