Timeline for Why is the electron-nucleus attraction modelled with only electrostatic interactions?
Current License: CC BY-SA 3.0
8 events
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| Jul 10, 2017 at 15:06 | history | edited | khaverim | CC BY-SA 3.0 |
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| Jul 8, 2017 at 15:47 | comment | added | khaverim | Yes: $F = k_e q_1 q_2 / r^2$ | |
| Jul 8, 2017 at 15:46 | comment | added | Abhinav Dhawan | So, it does not matter whether the charge is at rest or in motion. Only that it matters is its position and other charge. Thanks | |
| Jul 8, 2017 at 15:40 | comment | added | khaverim | It's called "-static" because the equation does not depend on time, but rather charge and position. But you can, and we do, use the equation at any point in time. The reason it is applied for electrons is no different than for a moving airplane. Everything is moving. If electrostatic interaction was that exclusive it wouldn't be relevant. | |
| Jul 8, 2017 at 15:36 | comment | added | Abhinav Dhawan | I'm just a beginner in the field of chemistry and not in a position to understand quantum mechanics . My question is simple. why the term "electrostatic attraction" is used when electrons are not stationary inside atoms but moving. | |
| Jul 8, 2017 at 14:24 | comment | added | khaverim | If "they" is electrons and neutrons, the answer is simple: they are not attracted. If "they" is electrons and nuclei, the answer is that Coulomb's equation is time independent, but it is re-calculated as a function of time, and it appears in the Hamiltonian used to calculate energy in time dependent and time-independent quantum mechanics via the Schrodinger equation. | |
| Jul 8, 2017 at 14:18 | comment | added | Abhinav Dhawan | I want to ask why they are attracted because of electrostatic attractions, even though electrostatics are for charges at rest. I think you got me wrong. | |
| Jul 8, 2017 at 14:13 | history | answered | khaverim | CC BY-SA 3.0 |