Timeline for On the stability of deuterium
Current License: CC BY-SA 3.0
3 events
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Jun 21 at 18:46 | comment | added | Oscar Lanzi | Technically protons would not remain fully stable. The antiproton generated in your reaction (which I recognize as $-1$ rather than $+1$ baryon) would consume a proton unfortunate enough to be at the wrong place and time. | |
May 11, 2017 at 21:12 | history | edited | jinawee | CC BY-SA 3.0 |
added 4 characters in body
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May 11, 2017 at 16:32 | history | answered | jinawee | CC BY-SA 3.0 |