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Timeline for On the stability of deuterium

Current License: CC BY-SA 3.0

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Jun 21 at 18:46 comment added Oscar Lanzi Technically protons would not remain fully stable. The antiproton generated in your reaction (which I recognize as $-1$ rather than $+1$ baryon) would consume a proton unfortunate enough to be at the wrong place and time.
May 11, 2017 at 21:12 history edited jinawee CC BY-SA 3.0
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May 11, 2017 at 16:32 history answered jinawee CC BY-SA 3.0