Timeline for Proof of Dynamic Nature of Equilibrium
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 26, 2020 at 10:07 | comment | added | Alchimista | Digestion and growing of the precipitate crystals is another hint, if not a proof. | |
| Aug 21, 2018 at 11:29 | answer | added | matt_black | timeline score: 2 | |
| May 7, 2017 at 17:09 | comment | added | TAR86 | @DoubtExpert The concentration is the same on either side of the wall before and after the removal - so I do not think there is a disturbance on a chemical level. Obviously, since the radioactive sugar is missing on one side (diffusion takes time), the solution is not homogenous, but that is the whole point. | |
| May 7, 2017 at 16:45 | comment | added | DoubtExpert | @J.Ari It maybe same. By adding radioactive sugar, aren't we increasing the mass of the precipitate and disturbing the original mass that was in equilibrium with the dissolved sugar? | |
| May 7, 2017 at 16:44 | comment | added | DoubtExpert | @TAR86 I am not sure whether on removal of the wall, the combined system (of two equilibria) is immediately in equilibrium. If this is false, then according to your example isn't this a disturbance? If the systems were assumed to be in static equilibrium, then due to this disturbance, it can be argued that the reactions would activate and this would lead radioactive sugar to be part of other container. | |
| Apr 27, 2017 at 4:18 | history | tweeted | twitter.com/StackChemistry/status/857448891809226752 | ||
| Apr 26, 2017 at 19:49 | comment | added | TAR86 | One would have the same effect by having two identical solutions (saturated, some solid sugar at the bottom), except that one is of radioactive sugar, with a removable wall in between. Some time after the removal, one would find radioactive sugar at the bottom of the container that initially only contained non-radioactive sugar. | |
| Apr 26, 2017 at 15:20 | answer | added | porphyrin | timeline score: 2 | |
| Apr 26, 2017 at 14:34 | comment | added | J. Ari | The importance is in how it is different. In this case, the different isotope of carbon will not be so different as to perceptibly affect the dissolution process. | |
| Apr 26, 2017 at 2:10 | answer | added | oldchemist | timeline score: 0 | |
| Apr 26, 2017 at 1:58 | comment | added | DoubtExpert | In that statement, I was referring to how it is proved generally (in chemical equilibrium as well). When I said another substance is added, I meant that - always something (same or different) is introduced from outside. And still isn't sugar with radioactive carbon different from that of normal carbon? | |
| Apr 25, 2017 at 19:19 | comment | added | J. Ari | For my clarification, why do you say that another substance is being added? To me, the description of the experiment says sugar (with radioactive carbon) is added to a saturated solution; sugar is being added to a sugar solution. | |
| S Apr 25, 2017 at 19:15 | history | suggested | Berry Holmes | CC BY-SA 3.0 |
Minor grammatical edits
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| Apr 25, 2017 at 19:01 | review | Suggested edits | |||
| S Apr 25, 2017 at 19:15 | |||||
| Apr 25, 2017 at 18:44 | review | First posts | |||
| Apr 25, 2017 at 19:01 | |||||
| Apr 25, 2017 at 18:41 | history | asked | DoubtExpert | CC BY-SA 3.0 |