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Sep 14, 2017 at 11:53 history edited andselisk
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Sep 14, 2017 at 11:13 answer added andselisk timeline score: 4
Sep 14, 2017 at 10:09 comment added Jan @IvanNeretin I wouldn’t exactly call cobalt(III) ‘unusually high’ …
Sep 14, 2017 at 10:08 history edited Jan CC BY-SA 3.0
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Sep 14, 2017 at 10:08 answer added Jan timeline score: 4
Apr 27, 2017 at 5:03 history edited Martin - マーチン CC BY-SA 3.0
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Apr 26, 2017 at 18:54 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Mar 27, 2017 at 18:28 history tweeted twitter.com/StackChemistry/status/846428848627560448
Mar 27, 2017 at 17:04 comment added Ivan Neretin Exactly. So in fact, the reasoning goes the other way around: first we find the distances, then we use those to deduce the oxidation states.
Mar 27, 2017 at 16:19 comment added orthocresol this is a case of the so-called "non-innocent" ligand: there is no way of knowing how $\ce{O2}$ as a ligand behaves without actually doing experiments on it (spectroscopy, diffraction, etc).
Mar 27, 2017 at 16:11 history edited TrY iS CheM CC BY-SA 3.0
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Mar 27, 2017 at 12:55 comment added Ivan Neretin We can't. It is a borderline case. With transition metals in unusually high oxidation states, you can never tell for sure by looking at the formula alone.
Mar 27, 2017 at 12:12 history asked TrY iS CheM CC BY-SA 3.0