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Jul 24, 2017 at 20:30 comment added jheindel @levineds Thanks for the reference. I see what you're saying and what they're saying. I should have been more precise when saying total energy. I have also since cleared up my confusion about the Fock operator and Fock matrix. Things were pretty jumbled but I'm glad to straighten them out!
Jul 24, 2017 at 18:46 comment added levineds No, again, the eigenvalues of the Fock matrix (which is the Fock operator in some basis) are the canonical orbital energies. Moreover, the sum of orbital energies is NOT the total system energy. Check out this paper for more info: pubs.acs.org/doi/abs/10.1021/ed200673w
Jul 24, 2017 at 15:32 vote accept jheindel
Jul 24, 2017 at 14:36 answer added Martin - マーチン timeline score: 17
Apr 13, 2017 at 12:57 history edited CommunityBot
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Apr 6, 2017 at 20:13 vote accept jheindel
Jul 24, 2017 at 15:32
Apr 6, 2017 at 3:11 history edited pentavalentcarbon
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Mar 18, 2017 at 3:09 answer added Tyberius timeline score: 11
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Mar 1, 2017 at 3:26 comment added jheindel Ah sorry. I was confusing the Fock matrix and the Fock operator. The eigenvalues of the Fock matrix are the energy of the whole system which corresponds to the sum of eigenvalues of the Fock operator which are indeed the orbital energies. Sorry to suggest otherwise. What I'm pointing out in the question is that the set of orbitals and their eigenvalues given by the Fock operator is not the only solution we could come up with. So, I'm basically asking what is so special about the HF orbitals that Koopmans' theorem should be so simple when that doesn't seem to be the case for other orbital sets.
Mar 1, 2017 at 0:52 comment added Greg They do, the Fock operator is an effective one electron operator and this is how you find the orbitals and the correspond energies.
Mar 1, 2017 at 0:45 comment added jheindel I don't think that the orbital energies ever correspond to the eigenvalues of the Fock operator. Rather the eigenvalues are the sum of these orbital energies, but I'm pretty sure these orbital energies are not unique because the orbitals themselves are not unique. The second half of that sentence depends on the answer to this question which I'm not completely sure of.
Mar 1, 2017 at 0:37 comment added Greg HOMO has a well defined energy only when it corresponds to an eigenvalue from HF. After such a unitary transformation the orbitals have no well defined energies any more
Feb 28, 2017 at 23:46 history edited jheindel CC BY-SA 3.0
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Feb 28, 2017 at 23:41 history asked jheindel CC BY-SA 3.0