Timeline for Constraints on the polar angle (θ) in the particle in a sphere problem
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Jun 11, 2020 at 10:20 | history | edited | CommunityBot |
Commonmark migration
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| Sep 8, 2017 at 15:37 | comment | added | Ivan Neretin | Yeah, now that's spot on. | |
| Sep 8, 2017 at 15:29 | comment | added | schneiderfelipe | I also further improved the answer. I hope it looks good now. | |
| Sep 8, 2017 at 15:28 | history | edited | schneiderfelipe | CC BY-SA 3.0 |
Further improved answer.
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| Sep 8, 2017 at 15:01 | comment | added | schneiderfelipe | I think it is still related to the question, since it addresses the fact that $\psi(\theta + \pi)$ is not necessarily equal to $\psi(\theta)$, as was asked, but I will rephrase it to make it more explicit. | |
| Sep 7, 2017 at 18:11 | comment | added | Ivan Neretin | That's good, but now your answer is unrelated to the question, since the latter was about $\theta+\pi$. | |
| Sep 7, 2017 at 15:42 | comment | added | schneiderfelipe | You're right, I edited and corrected the mistake. Thanks! | |
| Sep 7, 2017 at 15:41 | history | edited | schneiderfelipe | CC BY-SA 3.0 |
Corrected a bad mistake.
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| Sep 6, 2017 at 21:30 | comment | added | Ivan Neretin | You have it backwards. $\varphi\to\varphi+2\pi$ takes you to the same point on the sphere, so the value of $\psi$ must be the same. $\theta\to\theta+\pi$ takes you to a different point. | |
| Sep 6, 2017 at 20:50 | history | edited | schneiderfelipe | CC BY-SA 3.0 |
Improved grammar.
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| Feb 23, 2017 at 4:04 | vote | accept | BEWARB | ||
| Feb 19, 2017 at 14:26 | history | answered | schneiderfelipe | CC BY-SA 3.0 |