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Feb 6, 2020 at 16:40 history edited Karsten CC BY-SA 4.0
added 50 characters in body; edited title
May 23, 2018 at 7:50 answer added james timeline score: -1
Oct 9, 2017 at 2:56 answer added Mike timeline score: 2
May 24, 2017 at 5:19 comment added Pritt says Reinstate Monica Octet is not complete for carbon in (A). Option (B) is more stable with more octet satisfying atoms,
Aug 15, 2014 at 3:51 answer added Caters timeline score: -2
Mar 2, 2014 at 11:03 vote accept mikhailcazi
Oct 29, 2013 at 11:10 answer added Ben Norris timeline score: 13
Oct 29, 2013 at 10:13 history edited mikhailcazi CC BY-SA 3.0
added 309 characters in body
Oct 29, 2013 at 10:09 comment added mikhailcazi @SatwikPasani okay, so option (B) is more stable because 1) extra bond 2) carbon octet complete. Thanks! This helped.
Oct 28, 2013 at 20:13 comment added LordStryker @SatwikPasani Just for the sake of thoroughness, an oxygen pulls more electron density toward itself, not actual electrons themselves.
Oct 28, 2013 at 18:50 answer added William Everett timeline score: 2
Oct 26, 2013 at 13:56 comment added stochastic13 @mikhailcazi in general, oxygen does pull electrons towards itself in most resonating structures but can also donate an electron pair (acquire positive charge) if there is a positive charge on an adjacent carbon.
Oct 26, 2013 at 13:55 comment added stochastic13 @mikhailcazi That is because, relatively, as compared to other carbons, the one with a positive charge in one of the resonance structure is slightly positive and hence more prone to attack of nucleophile $\ce{Br-}$. It doesn't add on the oxygen because the lone pairs of oxygen in both the resonance structures repel the incoming nucleophile, which cannot form a bond with oxygen.
Oct 26, 2013 at 13:32 comment added F'x Between A and B, look at how the octet rule is satisfied for the carbon atom (and not the oxygen)…
Oct 25, 2013 at 15:39 history tweeted twitter.com/#!/StackChemistry/status/393763679650734080
Oct 25, 2013 at 14:37 comment added mikhailcazi While adding Br$^-$ to the compound, why do we take the reaction further by adding it to compound (A), then? :/
Oct 25, 2013 at 14:36 comment added mikhailcazi So you say that option (B) is more stable?
Oct 25, 2013 at 14:28 comment added stochastic13 I guess the octet is complete in both the cases. But for the stability of these resonance structures, points to considered in decreasing order of importance are higher number of bonds; complete octet; charge separation; +charge on electropositive and -charge on electronegative elements.
Oct 25, 2013 at 12:21 history edited mikhailcazi CC BY-SA 3.0
edited title
Oct 25, 2013 at 11:45 history asked mikhailcazi CC BY-SA 3.0