Timeline for Is Delta H = Delta U for bomb calorimeter or Delta H = Delta U + Delta n(g)RT?
Current License: CC BY-SA 3.0
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| Jan 13, 2017 at 14:48 | comment | added | porphyrin | While I agree with your 'red' comment we do not help ourselves when teaching and often use a variety of notation, e.g. such as G, $\Delta G$ and dG or create equations out of 'thin air' as $dU=(\partial U/\partial T)_VdT+(\partial U/\partial V)_TdV$. As an example, consider a change at constant volume then $\Delta V =0$ and so by the first law $q=\Delta U$. But $\Delta U$ is a function of state and q a path variable so how can this be? The answer is that the path is fixed so q is now a path function and should be changed, say, to $q_V$ . So the possibilities for confusion are many. | |
| Jan 4, 2017 at 13:26 | comment | added | Zhe | I wish I could frame the lines in red and put them up on a banner on the top of this site... | |
| Jan 4, 2017 at 13:14 | history | edited | orthocresol | CC BY-SA 3.0 |
added 32 characters in body
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| Jan 4, 2017 at 13:03 | history | answered | orthocresol | CC BY-SA 3.0 |