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Why does ClO4-ClO₄⁻ only have 3 double bonds?

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edit approved Oct 8, 2013 at 10:10
user1160
edit approved Oct 8, 2013 at 10:10
user1160

Why does $\ce{ClO4^{ClO4-}}$ only have 3 double bonds?

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edit approved Oct 8, 2013 at 9:05
ashu
edit approved Oct 8, 2013 at 9:05
ashu
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Why does ClO4$\ce{ClO4^{-}}$ only have 3 double bonds?

It seems that most people draw ClO4-$\ce{ClO4^{-}}$ with three double bonds and the negative charge on the oxygen: http://www.chemspider.com/Chemical-Structure.109953.html

However, it would seem that it is more stable for the negative charge to be on the chlorine as it is more electronegative? (thus giving 4 double bonds to each oxygen)

Why does ClO4- only have 3 double bonds?

It seems that most people draw ClO4- with three double bonds and the negative charge on the oxygen: http://www.chemspider.com/Chemical-Structure.109953.html

However, it would seem that it is more stable for the negative charge to be on the chlorine as it is more electronegative? (thus giving 4 double bonds to each oxygen)

Why does $\ce{ClO4^{-}}$ only have 3 double bonds?

It seems that most people draw $\ce{ClO4^{-}}$ with three double bonds and the negative charge on the oxygen: http://www.chemspider.com/Chemical-Structure.109953.html

However, it would seem that it is more stable for the negative charge to be on the chlorine as it is more electronegative? (thus giving 4 double bonds to each oxygen)

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theo1456
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