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Seems like the silicon atom is more oxophilic as compared to the phosphorus atom. This could in principal be explained by the higher strength of the $\mathrm{Si-O}$$\ce{Si-O}$ bond, as indicated by the dissociation energies $D$ (see http://www.wiredchemist.com/chemistry/data/bond_energies_lengths.html): $$ \mathrm{Si-O}:~~~~D=\mathrm{452~kJ/mol};~~~~r_b=163~\mathrm{pm} $$

$$ \mathrm{P-O}:~~~~D=\mathrm{335~kJ/mol};~~~~r_b=\mathrm{163~pm} $$$$\begin{array}{ccc} \hline \textbf{Bond} & \textbf{Dissociation energy / kJ mol}\mathbf{^{-1}} & \textbf{Bond length / pm} \\ \hline \ce{Si-O} & 452 & 163 \\ \ce{P-O} & 335 & 163 \\ \hline \end{array}$$ The $\mathrm{Si-O}$$\ce{Si-O}$ bond is stronger thus given an explanation why the Peterson olefination is favoured. It seems that the bond lengths $r_b$ are the same, though.

By the way, a nice discussion of oxophilicity was given recently in Inorg. Chem., 2016, 55 (18), 9461Inorg. Chem. 2016, 55 (18), 9461.

Seems like the silicon atom is more oxophilic as compared to the phosphorus atom. This could in principal be explained by the higher strength of the $\mathrm{Si-O}$ bond, as indicated by the dissociation energies $D$ (see http://www.wiredchemist.com/chemistry/data/bond_energies_lengths.html): $$ \mathrm{Si-O}:~~~~D=\mathrm{452~kJ/mol};~~~~r_b=163~\mathrm{pm} $$

$$ \mathrm{P-O}:~~~~D=\mathrm{335~kJ/mol};~~~~r_b=\mathrm{163~pm} $$ The $\mathrm{Si-O}$ bond is stronger thus given an explanation why the Peterson olefination is favoured. It seems that the bond lengths $r_b$ are the same, though.

By the way, a nice discussion of oxophilicity was given recently in Inorg. Chem., 2016, 55 (18), 9461.

Seems like the silicon atom is more oxophilic as compared to the phosphorus atom. This could in principal be explained by the higher strength of the $\ce{Si-O}$ bond, as indicated by the dissociation energies $D$ (see http://www.wiredchemist.com/chemistry/data/bond_energies_lengths.html): $$\begin{array}{ccc} \hline \textbf{Bond} & \textbf{Dissociation energy / kJ mol}\mathbf{^{-1}} & \textbf{Bond length / pm} \\ \hline \ce{Si-O} & 452 & 163 \\ \ce{P-O} & 335 & 163 \\ \hline \end{array}$$ The $\ce{Si-O}$ bond is stronger thus given an explanation why the Peterson olefination is favoured. It seems that the bond lengths $r_b$ are the same, though.

By the way, a nice discussion of oxophilicity was given recently in Inorg. Chem. 2016, 55 (18), 9461.

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Seems like the silicon atom is more oxophilic as compared to the phosphorus atom. This could in principal be explained by the higher strength of the $\mathrm{Si-O}$ bond, as indicated by the dissociation energies $D$ (see http://www.wiredchemist.com/chemistry/data/bond_energies_lengths.html): $$ \mathrm{Si-O}:~~~~D=\mathrm{452~kJ/mol};~~~~r_b=163~\mathrm{pm} $$

$$ \mathrm{P-O}:~~~~D=\mathrm{335~kJ/mol};~~~~r_b=\mathrm{163~pm} $$ The $\mathrm{Si-O}$ bond is stronger thus given an explanation why the Peterson olefination is favoured. It seems that the bond lengths $r_b$ are the same, though.

By the way, a nice discussion of oxophilicity was given recently in Inorg. Chem., 2016, 55 (18), 9461.