Timeline for Empirical formula when given percentages?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Apr 30, 2013 at 11:16 | comment | added | Unistudent9 | I see ^^ thankyou soo much! your explanation is so clear cut, thankyou for helping me to understand these questions! keep up the great work :) | |
| Apr 30, 2013 at 10:47 | comment | added | Ben Norris | When I went through the maths, I got $\ce{Pb3O4}$. Moles of lead $=90.66/207.2=0.4375$. Moles of oxygen $=9.34/16.00=0.5838$. Divide by the smaller number $0.4375$, and you get $\ce{Pb1O}_{1.33}$. 1.33 is too far from one to round (but it is $\frac{4}{3}$ to three sig figs). Multiply by 3: $\ce{Pb}_{1\times3} \ce{O}_{1.33\times3}=\ce{Pb3O4}$. | |
| Apr 30, 2013 at 10:27 | comment | added | Unistudent9 | Can I ask one more thing, I tried it I have the answer for your example and my example but for my question it says the answer is Pb3O4 where as I worked it out to be one : one moles in ratio, so PbO, the answers state that they are three : four atom ratio could you explain that by anychance? | |
| Apr 29, 2013 at 11:54 | vote | accept | Unistudent9 | ||
| Apr 28, 2013 at 10:51 | history | answered | Ben Norris | CC BY-SA 3.0 |