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Oct 24, 2015 at 20:03 comment added MaxW @orthocresol - I was thinking that this was a high school level question. But the answer from Wikipedia indicates a higher level of understanding would be required.
Oct 24, 2015 at 19:54 comment added orthocresol Well, the aromatic character of benzene is not exactly "fundamental" to MO theory - it is actually derived from the model. You can draw MO diagrams for the $\pi$ system of benzene without actually knowing that is it aromatic, and figure out from the diagrams that it is aromatic - which is the origin of Huckel's famous $(4n+2)$ rule... I mean, it's probably really just how you look at it. If you can get your hands on it, see Ian Fleming's Molecular Orbitals and Organic Chemical Reactions for a description.
Oct 24, 2015 at 19:53 history edited bon CC BY-SA 3.0
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Oct 24, 2015 at 19:51 history edited MaxW CC BY-SA 3.0
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Oct 24, 2015 at 19:50 comment added MaxW @Martin - "VB wave function" seems odd to me. (Granted my chemistry degree was earned when the four elements were air, water, earth and fire.) To me VB theory is more about the linear combination of atomic orbitals.
Oct 24, 2015 at 19:46 comment added MaxW @Bon - You're right about hybridization being part of Vb theory. I fixed that part.
Oct 24, 2015 at 19:44 history edited MaxW CC BY-SA 3.0
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Oct 24, 2015 at 19:31 comment added bon Also hybridization is part of VB not MO theory and VB theory does not predict alternating single and double bonds for benzene, it makes use of the concept of resonance to suggest a structure that is essentially the same as that suggested by MO.
Oct 24, 2015 at 19:12 comment added Martin - マーチン VB and MO will predict the same structure as the wave functions are essentially the same, if the description of complete. Differences do not carry any physical meaning and this is what the question is about.
Oct 24, 2015 at 18:23 history answered MaxW CC BY-SA 3.0