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Need to decide: you write either "oxygen" or you write "O2". There is no need to repeat yourself with redundant information and write "oxygen O2".
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Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammals. Simply put, it's a carrier protein. Interestingly it doesn't carry carbon dioxide in the same way it does for oxygen $\ce{O2}$. Oxygen binds to the iron atoms in the protein whereas carbon dioxide $\ce{CO2}$ is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide $\ce{CO}$ is a very aggressive molecule. It's a colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than oxygen does. It displaces oxygen and quickly binds, so very little oxygen is transported through the body cells.

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇌ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right, generating $\ce{Hb(CO)4(aq)}$, since its bond is much stronger.

I have two main related questions:

  1. Why is the carboxyhemoglobin bond stronger relative to that of oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammals. Simply put, it's a carrier protein. Interestingly it doesn't carry carbon dioxide in the same way it does for oxygen $\ce{O2}$. Oxygen binds to the iron atoms in the protein whereas carbon dioxide $\ce{CO2}$ is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide $\ce{CO}$ is a very aggressive molecule. It's a colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than oxygen does. It displaces oxygen and quickly binds, so very little oxygen is transported through the body cells.

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇌ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right, generating $\ce{Hb(CO)4(aq)}$, since its bond is much stronger.

I have two main related questions:

  1. Why is the carboxyhemoglobin bond stronger relative to that of oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammals. Simply put, it's a carrier protein. Interestingly it doesn't carry carbon dioxide in the same way it does for oxygen. Oxygen binds to the iron atoms in the protein whereas carbon dioxide is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide is a very aggressive molecule. It's a colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than oxygen does. It displaces oxygen and quickly binds, so very little oxygen is transported through the body cells.

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇌ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right, generating $\ce{Hb(CO)4(aq)}$, since its bond is much stronger.

I have two main related questions:

  1. Why is the carboxyhemoglobin bond stronger relative to that of oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

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Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammals. Simply put, it's a carrier protein. Interestingly it doesn't carry carbon dioxide in the same way it does for oxygen $\ce{O2}$. Oxygen binds to the iron atoms in the protein whereas carbon dioxide $\ce{CO2}$ is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide $\ce{CO}$ is a very aggressive molecule. It's a colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than oxygen does. It displaces oxygen and quickly binds, so very little oxygen is transported through the body cells.

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇋ Hb(CO)4 (aq)}$$$$\ce{Hb (aq) + 4CO (g) ⇌ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right, generating Hb(CO)4 (aq)$\ce{Hb(CO)4(aq)}$, since its bond is much stronger.

I have two main related questions:

  1. Why is the carboxyhemoglobin bond stronger relative to that of oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammals. Simply put, it's a carrier protein. Interestingly it doesn't carry carbon dioxide in the same way it does for oxygen $\ce{O2}$. Oxygen binds to the iron atoms in the protein whereas carbon dioxide $\ce{CO2}$ is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide $\ce{CO}$ is a very aggressive molecule. It's a colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than oxygen does. It displaces oxygen and quickly binds, so very little oxygen is transported through the body cells.

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇋ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right, generating Hb(CO)4 (aq), since its bond is much stronger.

I have two main related questions:

  1. Why is the carboxyhemoglobin bond stronger relative to that of oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammals. Simply put, it's a carrier protein. Interestingly it doesn't carry carbon dioxide in the same way it does for oxygen $\ce{O2}$. Oxygen binds to the iron atoms in the protein whereas carbon dioxide $\ce{CO2}$ is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide $\ce{CO}$ is a very aggressive molecule. It's a colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than oxygen does. It displaces oxygen and quickly binds, so very little oxygen is transported through the body cells.

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇌ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right, generating $\ce{Hb(CO)4(aq)}$, since its bond is much stronger.

I have two main related questions:

  1. Why is the carboxyhemoglobin bond stronger relative to that of oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

Clarified title, added tag, minor typesetting.
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Todd Minehardt
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Why does carbon monoxide hashave a greater affinity for Hemoglobin compared tohemoglobin than oxygen?

Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammaliansmammals. Simply put, it's a carrier protein. Interestingly it doesn't carry carbon dioxide in the same way it does for oxygen $\ce{O2}$. Oxygen binds to the iron atoms in the protein whereas carbon dioxide $\ce{CO2}$ is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide $\ce{CO}$ is a very aggressive molecule. It's a colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than does oxygen does. It surpassesdisplaces oxygen and quickly binds, in fact tricks hemoglobin, so very little oxygen is transported through the body cells. Of course, the oxygen deficiency doesn't result in anything pleasant...

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇋ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right, generating Hb(CO)4 (aq), since its bond is much stronger. I

I have two main related questions:

  1. Why is the carboxyhemoglobin bond stronger relative to that of oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

Why carbon monoxide has a greater affinity for Hemoglobin compared to oxygen?

Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammalians. Simply put it's a carrier protein. Interestingly it doesn't carry carbon dioxide the same way it does for oxygen $\ce{O2}$. Oxygen binds to the iron atoms in the protein whereas carbon dioxide $\ce{CO2}$ is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide $\ce{CO}$ is a very aggressive molecule. It's colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than does oxygen. It surpasses oxygen and quickly binds, in fact tricks hemoglobin, so very little oxygen is transported through the body cells. Of course, the oxygen deficiency doesn't result in anything pleasant...

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇋ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right generating Hb(CO)4 (aq) since its bond is much stronger. I have two main related questions:

  1. Why is carboxyhemoglobin bond stronger relative to oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

Why does carbon monoxide have a greater affinity for hemoglobin than oxygen?

Hemoglobin is an iron-containing oxygen transport metalloprotein in the red blood cells of most mammals. Simply put, it's a carrier protein. Interestingly it doesn't carry carbon dioxide in the same way it does for oxygen $\ce{O2}$. Oxygen binds to the iron atoms in the protein whereas carbon dioxide $\ce{CO2}$ is bound to the protein chains of the structure. Carbon dioxide doesn't compete with oxygen in this binding process.

However, carbon monoxide $\ce{CO}$ is a very aggressive molecule. It's a colourless, odourless, and tasteless gas that is lighter than air and can be fatal to life. It has a greater affinity for hemoglobin than oxygen does. It displaces oxygen and quickly binds, so very little oxygen is transported through the body cells.

There are two equilibrium reactions of binding oxygen and becoming oxygenated hemoglobin:

$$\ce{Hb (aq) + 4O2 (g) -> Hb(O2)4 (aq)}$$

$$\ce{Hb (aq) + 4O2 (g) <- Hb(O2)4 (aq)}$$

And carbon monoxide binding equation at equilibrium:

$$\ce{Hb (aq) + 4CO (g) ⇋ Hb(CO)4 (aq)}$$

It is said the equation is shifted towards right, generating Hb(CO)4 (aq), since its bond is much stronger.

I have two main related questions:

  1. Why is the carboxyhemoglobin bond stronger relative to that of oxygenated hemoglobin?

  2. Why is carbon monoxide highly attracted to hemoglobin?

Does it have anything to do with the oxidation state of oxygen in each molecule? Please show some reaction equations associating $\ce{Fe}$.

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