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Nov 15, 2019 at 22:16 comment added ron @PCK There is no circularity in the argument. Unless there is some outside influence that affects the two nitro groups differently (e.g. crystal packing forces in a solid), then the nitro groups must be equivalent.
Nov 14, 2019 at 15:40 comment added PCK Ha, just seen how old this is
Nov 14, 2019 at 15:39 comment added PCK I agree with much of this, but isnt there some circularity in this argument? The C2 symmetry axis only exists IF the C-N bonds are equivalent, so we shouldn't use it as proof of their equivalence?
Jun 25, 2015 at 17:36 history answered ron CC BY-SA 3.0