$$\mathrm{N}_2+\mathrm{O}_2\rightarrow \mathrm{N}_x\mathrm{O}_y$$$$\ce{N2 +O2 -> N_{$x$}O_{$y$}}$$ Now using POAC (Principle of Atomic conservation), $$\frac5{28}.2=\frac{19.3}{14x+16y}.x\implies \frac yx\approx2.5025\sim2.5\implies y'=5,x'=2\implies \mathrm{N}_2\mathrm{O}_5$$$$\frac5{28}\cdot2=\frac{19.3}{14x+16y}\cdot x\implies \frac{y}{x}\approx2.5025\sim2.5\implies y'=5,x'=2\implies \ce{N2O5}$$