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Mar 20 at 8:03 comment added Anjankumar it ain't planar
Mar 19 at 20:45 history edited Loong CC BY-SA 4.0
names added
Mar 19 at 19:28 comment added Mathew Mahindaratne All $\mathrm{sp^3}$ hybrids are tetrahedral, which have two planes perpendicular to each other such as $\ce{CH4}$. Thus, all your four structures show in here are not planer. So, could have some mirror images not equal.
S Mar 19 at 19:15 history suggested Harikrishnan M CC BY-SA 4.0
Changed all handwritten pics to structures.
Mar 19 at 16:02 review Suggested edits
S Mar 19 at 19:15
Mar 19 at 15:47 answer added afrin timeline score: 1
Mar 19 at 11:59 comment added Ninjametry are you talking about the first structure? If yes , then arent Br , Cl is same plane because spiro rings are perpendicular to each other , and there are three of them .... so they will be in same plane and hence show GI
Mar 19 at 4:24 comment added Mathew Mahindaratne Think again. Are really Br and Cl in same plane with C atoms?
S Mar 19 at 1:38 review First questions
Mar 19 at 4:25
S Mar 19 at 1:38 history asked Ninjametry CC BY-SA 4.0