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Jan 13, 2023 at 1:00 comment added Oscar Lanzi My interpretation is that water and oxygen are both reactants in the half equation $\ce{2 H2O + O2 +4e^- -> 4 OH^-}$. Rust formation mechanisms I have seen must include ferrous hydroxide be assembled iron(II) and hydroxide ions are formed to begin the process. See for instance en.wikipedia.org/wiki/Rust.
Jan 13, 2023 at 0:34 comment added jimchmst Dissolved O2 oxidizes Fe+2 to Fe+3. It is not necessary for the reaction of Fe with water to give ferrous hydroxide. Water is reduced to H2 not to hydroxide ions. the latter have no change in oxidation state.
Jan 12, 2023 at 1:24 history answered Oscar Lanzi CC BY-SA 4.0