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Waylander
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Nitrogen pentoxide is a good source of $\ce{NO2^+}$ (in fact the solid form directly contains $\ce{NO2^+}$). So, as you imply, we would expect a nitration reaction especially with an activating, ortho-para directing substituent such as the alkoxy group shown.

The ortho product would be favored by hydrogen bonding, but here there is no hoodgood mechanisms for that. Hydrogen bonding with hydrogen attached to carbon may actually be possible, but it is weak, and the nitrogen group will not provide more strongly protection hydrogen. Therefore the more sterically favored para product would be major.

Nitrogen pentoxide is a good source of $\ce{NO2^+}$ (in fact the solid form directly contains $\ce{NO2^+}$). So, as you imply, we would expect a nitration reaction especially with an activating, ortho-para directing substituent such as the alkoxy group shown.

The ortho product would be favored by hydrogen bonding, but here there is no hood mechanisms for that. Hydrogen bonding with hydrogen attached to carbon may actually be possible, but it is weak, and the nitrogen group will not provide more strongly protection hydrogen. Therefore the more sterically favored para product would be major.

Nitrogen pentoxide is a good source of $\ce{NO2^+}$ (in fact the solid form directly contains $\ce{NO2^+}$). So, as you imply, we would expect a nitration reaction especially with an activating, ortho-para directing substituent such as the alkoxy group shown.

The ortho product would be favored by hydrogen bonding, but here there is no good mechanisms for that. Hydrogen bonding with hydrogen attached to carbon may actually be possible, but it is weak, and the nitrogen group will not provide more strongly protection hydrogen. Therefore the more sterically favored para product would be major.

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Oscar Lanzi
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Nitrogen pentoxide is a good source of $\ce{NO2^+}$ (in fact the solid form directly contains $\ce{NO2^+}$). So, as you imply, we would expect a nitration reaction especially with an activating, ortho-para directing substituent such as the alkoxy group shown.

Can you continue fromThe ortho product would be favored by hydrogen bonding, but here there? is no hood mechanisms for that. Hydrogen bonding with hydrogen attached to carbon may actually be possible, but it is weak, and the nitrogen group will not provide more strongly protection hydrogen. Therefore the more sterically favored para product would be major.

Nitrogen pentoxide is a good source of $\ce{NO2^+}$ (in fact the solid form directly contains $\ce{NO2^+}$). So we would expect a nitration reaction especially with an activating, ortho-para directing substituent such as the alkoxy group shown.

Can you continue from there?

Nitrogen pentoxide is a good source of $\ce{NO2^+}$ (in fact the solid form directly contains $\ce{NO2^+}$). So, as you imply, we would expect a nitration reaction especially with an activating, ortho-para directing substituent such as the alkoxy group shown.

The ortho product would be favored by hydrogen bonding, but here there is no hood mechanisms for that. Hydrogen bonding with hydrogen attached to carbon may actually be possible, but it is weak, and the nitrogen group will not provide more strongly protection hydrogen. Therefore the more sterically favored para product would be major.

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Oscar Lanzi
  • 62.5k
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  • 187

Nitrogen pentoxide is a good source of $\ce{NO2^+}$ (in fact the solid form directly contains $\ce{NO2^+}$). So we would expect a nitration reaction especially with an activating, ortho-para directing substituent such as the alkoxy group shown.

Can you continue from there?